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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeA and B can complete a work in 10 days and 15 days respectively. They undertook to do a job for Rs 3000. Now with the help of C they did in 4 days. What will B get as his share?
Correct
Explanation:
1/10 + 1/15 + 1/x = 1/4
So x = 12 days, C can do in 12 days
So money will be shared in ratio 1/10 : 1/15 : 1/12 = 6 : 4 : 5
So B will get = 4/15 * 3000Incorrect
Explanation:
1/10 + 1/15 + 1/x = 1/4
So x = 12 days, C can do in 12 days
So money will be shared in ratio 1/10 : 1/15 : 1/12 = 6 : 4 : 5
So B will get = 4/15 * 3000 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeSelling price of an article is set at Rs 2200. If it was sold at 20% less, then also there would have a profit of 10%. What is the actual cost price of the article?
Correct
Explanation:
SP = (80/100)*2200 = 1760
So CP = (100/110)* 1760Incorrect
Explanation:
SP = (80/100)*2200 = 1760
So CP = (100/110)* 1760 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeThere are 1000 boys and 800 girls in a school. 70% of the boys and 90% of the girls passed in an examination. What is the approximate percentage of students who did not pass that exam?
Correct
Explanation:
Boys who dint pass = (30/100)*1000 = 300
Girls who dint pass = (10/100)*800 = 80
Total who dint pass = 300+80 = 380 out of total 1000+800 = 1800 students
So required % = (380/1800)*100Incorrect
Explanation:
Boys who dint pass = (30/100)*1000 = 300
Girls who dint pass = (10/100)*800 = 80
Total who dint pass = 300+80 = 380 out of total 1000+800 = 1800 students
So required % = (380/1800)*100 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeIf 3x + 4y = 23 and 7x + 2y = 28, then 3x + 10y equals
Correct
Explanation:
Solving equations gives, x = 3, y = 3.5
So 3x + 10y = 3*3 + 10*3.5Incorrect
Explanation:
Solving equations gives, x = 3, y = 3.5
So 3x + 10y = 3*3 + 10*3.5 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeA sum of money amounts to Rs 2360 in 2 years and Rs 2900 in 5 years. The rate of interest per annum is
Correct
Explanation:
P + SI for 2 yrs = 2360
P + SI for 5 yrs = 2900
Subtract these equations, So SI for 3 yrs = 540
So SI for 1 yr = 540/3 = Rs 180
So P + SI for 2 yrs = 2360 gives
P + 2*180 = 2360,
Solve, P = 2000
Now 180 = 2000*r*1/100
Solve, r = 9Incorrect
Explanation:
P + SI for 2 yrs = 2360
P + SI for 5 yrs = 2900
Subtract these equations, So SI for 3 yrs = 540
So SI for 1 yr = 540/3 = Rs 180
So P + SI for 2 yrs = 2360 gives
P + 2*180 = 2360,
Solve, P = 2000
Now 180 = 2000*r*1/100
Solve, r = 9 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeA and B invested in a business as Rs 3000 and Rs 4500 respectively. After 4 months C joins with Rs 3600. If after a year, C gets Rs 3040 as his share of profit, what is the share of A?
Correct
Explanation:
3000*12 : 4500*12 : 3600*8
10 : 15 : 8
so (8)/(10+15+8) * x= 3040
solve, x = 12540
so A’s share = 10/33 * 12540Incorrect
Explanation:
3000*12 : 4500*12 : 3600*8
10 : 15 : 8
so (8)/(10+15+8) * x= 3040
solve, x = 12540
so A’s share = 10/33 * 12540 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative Aptitude2 years hence, the sum of ages of Arun and Ridhima will be 32 years. Also 5 years ago, the ratio of their ages was 7 : 11 respectively. What will be Arun’s age 8 years hence?
Correct
Explanation:
7x and 11x
Now (5+2) = 7 yrs
So (7x+7) + (11x+7) = 32
Solve, x = 1
So Arun’s present age = 7x+5 = 12
So after 8 yrs = 12+8Incorrect
Explanation:
7x and 11x
Now (5+2) = 7 yrs
So (7x+7) + (11x+7) = 32
Solve, x = 1
So Arun’s present age = 7x+5 = 12
So after 8 yrs = 12+8 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeHow many 4 letter words starting with vowel can be formed by the letters of word UPSTREAM such that no letter repeats?
Correct
Explanation:
There are 3 vowels, so we gave 3 choices for the first letter
There are total 8 letters in UPSTREAM, and one of them has occupied first place, so 7 choices for second, 6 choices for third, and 5 choices for fourth
So 3*7*6*5 = 630Incorrect
Explanation:
There are 3 vowels, so we gave 3 choices for the first letter
There are total 8 letters in UPSTREAM, and one of them has occupied first place, so 7 choices for second, 6 choices for third, and 5 choices for fourth
So 3*7*6*5 = 630 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeWhat is the LCM of 2/5, 4/25, 6/11, 10/22?
Correct
Explanation:
LCM will be LCM of numerators/HCF of denominators
So LCM = (LCM of 2,4,6,10)/(HCF of 5,25, 11, 22)
= 60/1Incorrect
Explanation:
LCM will be LCM of numerators/HCF of denominators
So LCM = (LCM of 2,4,6,10)/(HCF of 5,25, 11, 22)
= 60/1 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeA boat can travel 15 km upstream in 30 minutes. If the speed of the current is 1/3 of the speed of the boat in still water, how much distance can the boat travel downstream in 30 minutes?
Correct
Explanation:
A boat can travel 15 km upstream in 30 minutes. So Upstream speed = 15 / (30/60) = 30 km/hr
Let speed of the boat in still water = x
Speed of the current = x/3
Upstream speed = x – x/3 = 2x/3
But from above Upstream speed = 30. So 2x/3 = 30
Solve, x = 45
Speed of the current = 45/3 = 15 and speed of boat = 45
Downstream speed = 45+15 = 60
Distance travelled in 30min = 60 * (30/60)= 30 kmIncorrect
Explanation:
A boat can travel 15 km upstream in 30 minutes. So Upstream speed = 15 / (30/60) = 30 km/hr
Let speed of the boat in still water = x
Speed of the current = x/3
Upstream speed = x – x/3 = 2x/3
But from above Upstream speed = 30. So 2x/3 = 30
Solve, x = 45
Speed of the current = 45/3 = 15 and speed of boat = 45
Downstream speed = 45+15 = 60
Distance travelled in 30min = 60 * (30/60)= 30 km
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