Hello Aspirants,
Welcome to Online Quant Test in AffairsCloud.com. We are starting Railway RRB 2016 and we are creating sample questions in Quant section, type of which will be asked in Railway RRB 2016!!!
 Click Here to View Stratus: Railway RRB 2016 Course
 Railway RRB 2016: Reasoning Test
 Railway RRB 2016: Quants Test
 Railway RRB 2016: General Awareness Test
Help: Share Our Railway RRB 2016 Course page to your Friends & FB Groups
_____________________________________________________________________
Quizsummary
0 of 10 questions completed
Questions:
 1
 2
 3
 4
 5
 6
 7
 8
 9
 10
Information
All the Best
You have already completed the quiz before. Hence you can not start it again.
Quiz is loading...
You must sign in or sign up to start the quiz.
You have to finish following quiz, to start this quiz:
Results
0 of 10 questions answered correctly
Your time:
Time has elapsed
You have reached 0 of 0 points, (0)
Categories
 Quantitative Aptitude 0%
 1
 2
 3
 4
 5
 6
 7
 8
 9
 10
 Answered
 Review

Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeA bag contains 25 paise, 50 paise, and Rs 2 coins in the ratio 12 : 15 : 20 respectively. If the total value of money in bag is Rs 505, what is the total number of coins in the bag?
Correct
Explanation:
Coins – 12x, 15x, 20x, so
Value of 25 paise coins = (25/100)*12x = 3x, of 50 paise coin = (50/100)*15x = 15x/2, of Rs 2 coins = 2*20x = 40x
So total value is 3x+(15x/2)+40x = 101x/2 which equals 505, so x = 10
Total coins = 12x+15x+20x = 47x = 470Incorrect
Explanation:
Coins – 12x, 15x, 20x, so
Value of 25 paise coins = (25/100)*12x = 3x, of 50 paise coin = (50/100)*15x = 15x/2, of Rs 2 coins = 2*20x = 40x
So total value is 3x+(15x/2)+40x = 101x/2 which equals 505, so x = 10
Total coins = 12x+15x+20x = 47x = 470 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative Aptitude36, 18, 18, 27, 54, ?
Correct
Explanation:
36*0.5, 18*1, 18*1.5, 27*2, 54*2.5,Incorrect
Explanation:
36*0.5, 18*1, 18*1.5, 27*2, 54*2.5, 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeHow many kg of wheat costing Rs 10 per kg must be mixed with 16 Kg of wheat costing Rs 15 per Kg, so that there may be gain of 30% by selling the mixture of Rs 15.6 per Kg?
Correct
Explanation:
With 30% gain and SP = 15.6, CP = (100/130)*15.6 = 12
By method of allegation:
1st wheat (x kg)…………..2nd wheat (16 kg)
10……………………………..…….15
.,…………………..12
3………………………………………2
3 : 2
So x/16 = 3/2
Solve, x = 24Incorrect
Explanation:
With 30% gain and SP = 15.6, CP = (100/130)*15.6 = 12
By method of allegation:
1st wheat (x kg)…………..2nd wheat (16 kg)
10……………………………..…….15
.,…………………..12
3………………………………………2
3 : 2
So x/16 = 3/2
Solve, x = 24 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeA and B can complete a work in 40 and 60 days respectively. They started a work which is to be completed in 20 days. But it was found that they will not be able to complete work on time, so a third person C was appointed after 12 days. In how many days C can alone complete the work?
Correct
Explanation:
A and B worked for 20 days. In 1 day they could have completed work (1/40 + 1/60) = 1/24
So in 20 days, they did (1/24)*20 = 5/6
This means C did 1 – 5/6 = 1/6 of work in 8 days because he joined after 12 days and up to 20 days.
So he can do 1 work in 48 daysIncorrect
Explanation:
A and B worked for 20 days. In 1 day they could have completed work (1/40 + 1/60) = 1/24
So in 20 days, they did (1/24)*20 = 5/6
This means C did 1 – 5/6 = 1/6 of work in 8 days because he joined after 12 days and up to 20 days.
So he can do 1 work in 48 days 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeA train starts from station A at 7:00 AM and reaches station B at 9:00 AM. Another train starts from station B at 7:30 AM and reaches station A at 10:30 AM. At what time the two trains will meet?
Correct
Explanation:
Let the distance from A to B is ‘d’ km.
First train reaches destination in 2 hrs, so speed of first train = d/2 km/hr.
Speed of second train = d/3 km/hr
Speed of first train = d/2 km/hr, so after 1/2 hr, i.e. at 7:30 AM, the first train has covered d/4 km.
The distance left = (d – d/4) km = 3d/4 km. relative speed = d/2 + d/3.
So time they will meet at = 7:30 AM + (3d/4) / (d/2 + d/3)
= 7:30 AM + (9/10)*60 = 8:24 AMIncorrect
Explanation:
Let the distance from A to B is ‘d’ km.
First train reaches destination in 2 hrs, so speed of first train = d/2 km/hr.
Speed of second train = d/3 km/hr
Speed of first train = d/2 km/hr, so after 1/2 hr, i.e. at 7:30 AM, the first train has covered d/4 km.
The distance left = (d – d/4) km = 3d/4 km. relative speed = d/2 + d/3.
So time they will meet at = 7:30 AM + (3d/4) / (d/2 + d/3)
= 7:30 AM + (9/10)*60 = 8:24 AM 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeAn article is marked 25% above the cost price with marked price being Rs 150. The profit gets increased by Rs 6.9, when the selling price of this article is increased by 5%. What is the original selling price of the article?
Correct
Explanation:
5% of SP= 6.9
then 100% of SP= 6.9×100/5 =138Incorrect
Explanation:
5% of SP= 6.9
then 100% of SP= 6.9×100/5 =138 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeThe ratio of the areas of the circumcircle and the incircle of an equilateral triangle is
Correct
Explanation:
For equi. Triangle
Inradius = a/2√3
Circumradius = a/√3
So ratio is
ᴨ (a/√3)^2 : ᴨ (a/2√3)^2
= 4 : 1Incorrect
Explanation:
For equi. Triangle
Inradius = a/2√3
Circumradius = a/√3
So ratio is
ᴨ (a/√3)^2 : ᴨ (a/2√3)^2
= 4 : 1 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeIf [2x + (1/3x)] = 5, then value of 5x/(6x^2 + 20x +1) is
Correct
Explanation:
[2x + (1/3x)] = 5
So 6x^2 + 1 =15x
Add 20 x to both sides
6x^2 + 20x + 1 =15x + 20x = 35x
So 5x/(6x^2 + 20x +1) = 5x/35x = 1/7Incorrect
Explanation:
[2x + (1/3x)] = 5
So 6x^2 + 1 =15x
Add 20 x to both sides
6x^2 + 20x + 1 =15x + 20x = 35x
So 5x/(6x^2 + 20x +1) = 5x/35x = 1/7 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeIf A = tan 11.tan 29, B = 2 cot 61.cot79, then:
Correct
Explanation:
B = 2 cot 61.cot79
B = 2 cot (9029). cot (9011) = 2 tan 29.tan 11 = 2AIncorrect
Explanation:
B = 2 cot 61.cot79
B = 2 cot (9029). cot (9011) = 2 tan 29.tan 11 = 2A 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeConsider the data set {5, 2, 3, 8, 9}. The variance of set is
Correct
Explanation:
Variance = [ ( (510)^2+(210)^2+(310)^2+(810)^2+(910)^2 )/5 ]
= [ (25 + 64 + 49 + 4 + 1)/5 ] = 28.6Incorrect
Explanation:
Variance = [ ( (510)^2+(210)^2+(310)^2+(810)^2+(910)^2 )/5 ]
= [ (25 + 64 + 49 + 4 + 1)/5 ] = 28.6
 Note: We are providing unique questions for you to practice well, have a try !!
 Ask your doubt in comment section, AC Mod’s ll clear your doubts in caring way.
 – E.g: @shubhra “Hi, Can You Explain 8th Question?”