Hello Aspirants. Welcome to Online Quantitative Aptitude Section with explanation in AffairsCloud.com. Here we are creating question sample in Ages which is common for all competitive exams. We have included Some questions that are repeatedly asked in bank exams !!!
- Suman’s age was double that of Kareena’s 10 years ago. Ratio of the present ages of Kareena to Suman is 3 : 5. What will be Kareena’s age 5 years after?
A) 50
B) 30
C) 65
D) 35
E) 40D) 35
Explanation:
Let the present ages of Kareena and Suman are 3x and 5x.
Then, 10 yrs ago, (5x-10) = 2 * (3x-10)
Solve, x = 10
So Kareena present age = 30, after 5 years = 35 - 8 years ago, Bhanu’s age was four greater than Ravi’s age that time. Also the ratio of Ravi’s age to Bhanu’s 8 years after will be 6 : 7. Find the ratio of Ravi’s age to that of Bhanu’s age 4 years after.
A) 2 : 3
B) 4 : 9
C) 7 : 5
D) 6 : 5
E) 5 : 6E) 5 : 6
Explanation:
Ravi = x, Bhanu = y
8 years ago, (x-8) + 4 = (y-8) . This gives x – y = -4
After 8 years, (x+8)/ (y+8) = 6/7. This gives 7x – 6y = -8
Solve both equations, x = 16, y = 20
So required ratio = (16+4) : (20+4) = 20 : 24 = 5 : 6 - Ratio of Rani’s age to Sheena’s age was 5 : 8 four years ago. Sheena’s present age is 6 years greater than Rani’s age 6 years after. Find the ratio of the present ages of Sheena and Rani.
A) 2 : 3
B) 3 : 2
C) 4 : 5
D) 5: 6
E) None of theseB) 3 : 2
Explanation:
Rani = A, Sheena = B
4 yrs ago, A-4/B-4 = 5/8
8A – 5B = 12
After 6 yrs, A + 6 = B – 6
Solve the equations, A = 24, B = 36 - Kavya’s age is 3 times more than that of Rita. Kavya will be 2 ½ times that of Rita 8 years after. How many times will Kavya’s age be that of Rita 8 more years after?
A) 2 n half
B) 2
C) 3
D) 3 n half
E) 1 n halfB) 2
Explanation:
Rita = x, Kavya = x+3x = 4x
(4x + 8) = 5/2 (x+8)
Solve, x = 8
After 8 years, Kayva = 4x + 16 = 48, Rita = x+16 = 24 - Ronit’s age is 10 years more than Rohit’s age. Also Ronit was twice old as Rohit 15 years ago. What will be the age of Ronit 6 years after?
A) 41
B) 40
C) 35
D) 45
E) 38A) 41
Explanation:
Rohit = x, Ronit = x+10
(x+10) – 15 = 2(x-15)
Solve, x = 25
Ronit’s 6 years after = x+10+6 - Ravi’s age was one third of his father’s 18 years ago. Now he is half the age of his father. What is the difference in the present ages of father and Ravi?
A) 72
B) 36
C) 25
D) 20
E) 30B) 36
Explanation:
Ravi’s present = x, father’s = 2x
Then, (2x-18) = 3 (x – 18)
Solve, x = 36
So difference = 2x-x = x = 36 - Kirti’s age 4 years ago and Kavita’s 4 years hence is same. Also the present ages of Kirti and Kavita are in the ratio 5 : 3. Find the ratio of Kirti’s age 4 years hence to Kavita’s age 4 years ago.
A) 3 : 2
B) 5 : 2
C) 3 : 1
D) 2 : 3
E) 1 : 3C) 3 : 1
Explanation:
Kirti = A, Kavita = B
Let A’s present age = 5x, and B’s = 3x
A’s age 4 years ago to B’s age 4 years hence is same
So (5x-4) = (3x+4)
Solve x = 4
So A’s present age = 20, and B’s = 12
Required ratio = (20+4) : (12-4) - The sum of ages of Sonu and Monu is 60 at present. Also Sonu’s age was five time that of Monu 6 years ago. What will be the age of Monu 5 years after?
A) 14
B) 20
C) 18
D) 19
E) 22D) 19
Explanation:
Monu = x, Sonu = 60-x
60-x – 6 = 5*(x – 6)
solve, x = 14
monu’s 5 years after = x+5 = 19 - Reema’s age will be 7/3 of Tina’s 6 years after. Also the ratio of their ages was 5 : 1, 10 years ago. What is Reema’s present age?
A) 45
B) 50
C) 30
D) 60
E) None of theseB) 50
Explanation:
Let 10 years ago, Tina = x, Reema = 5x
Then, 5x+16 = 7/3 * (x+16)
Solve, x = 8
So Reema’s present age = 5x+10 = 50 - The ratio of Shruti’s age to Meenu’s age is 5 : 7. The difference in the present age of Meenu and Shruti’s age 6 years after is 2 years. What is the total of their present ages?
A) 45
B) 48
C) 50
D) 60
E) None of theseB) 48
Explanation:
Shruti = 5x, Meenu = 7x
7x – (5x+6) = 2
Solve, x = 4
So sum = 5x+7x = 12x = 48
AffairsCloud Recommends Oliveboard Mock Test
AffairsCloud Ebook - Support Us to Grow
Govt Jobs by Category
Bank Jobs Notification
