# IBPS Clerk 2018 Mains: Reasoning Test Day 19

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- Question 1 of 10
##### 1. Question

1 pointsCategory: Reasoning**(Directions 1 – 5): To answer the questions, study the following example based on the corresponding conditions given below it.**1. If the sum of two digits in triangle 1 is less than 10, then increase each digits by 2 and then take the sum else decrease the digits by 2 and then take the product.

2. If the number of alphabets in English alphabet series between the 2 letters in triangle 2 is odd, then each alphabet is changed to their immediate successive alphabet in the alphabetical series else each alphabet is changed to their immediate preceding alphabet in the alphabet series.

3. If the product of two digits in triangle 3 is greater than 15, then increase digits by 1 and take the product else take the sum of two digits.

4. If the difference in the position of alphabets(in English alphabet series) of the two alphabets in triangle 4 is less than 10, then the alphabet exchange their positions to their respective immediate succeeding alphabets in the alphabetical series else alphabets exchange their positions in the triangle.Example:

**Question Figure:**

CorrectAnswer –

**3**

Solution:

According to given conditions:

In triangle 1:

Sum of digits = 6 + 5 = 11.

Sum of digits > 10 it implies decrease each digit by 2 and take the product.

6 – 2 = 4, 5 – 2 = 3 → Product of 4 × 3 = 12.In triangle 2:

Number of letters between ‘h’ and ‘p’ = 7.

Number of letters is odd. It implies change each alphabet to their immediate succeeding alphabet.

‘h’ → ‘i’ and ‘p’ → ‘q’In triangle 3:

Product of 3 and 6 = 3 × 6 = 18

Product of two digits > 15 it implies increase each digit by 1 and take the product.

3 + 1 = 4, 6 + 1 = 7 → Product of 4 × 7 = 28In triangle 4:

Difference in position of alphabets ‘l’(12) and ‘t’(20) is 20 – 12 = 8

Difference in position of alphabets < 10 it implies exchange the position of alphabets to their respective immediate succeeding alphabets.

‘l’ → ‘m’ and ‘t’ → ‘u’

IncorrectAnswer –

**3**

Solution:

According to given conditions:

In triangle 1:

Sum of digits = 6 + 5 = 11.

Sum of digits > 10 it implies decrease each digit by 2 and take the product.

6 – 2 = 4, 5 – 2 = 3 → Product of 4 × 3 = 12.In triangle 2:

Number of letters between ‘h’ and ‘p’ = 7.

Number of letters is odd. It implies change each alphabet to their immediate succeeding alphabet.

‘h’ → ‘i’ and ‘p’ → ‘q’In triangle 3:

Product of 3 and 6 = 3 × 6 = 18

Product of two digits > 15 it implies increase each digit by 1 and take the product.

3 + 1 = 4, 6 + 1 = 7 → Product of 4 × 7 = 28In triangle 4:

Difference in position of alphabets ‘l’(12) and ‘t’(20) is 20 – 12 = 8

Difference in position of alphabets < 10 it implies exchange the position of alphabets to their respective immediate succeeding alphabets.

‘l’ → ‘m’ and ‘t’ → ‘u’

- Question 2 of 10
##### 2. Question

1 pointsCategory: Reasoning**(Directions 1 – 5): To answer the questions, study the following example based on the corresponding conditions given below it.**1. If the sum of two digits in triangle 1 is less than 10, then increase each digits by 2 and then take the sum else decrease the digits by 2 and then take the product.

2. If the number of alphabets in English alphabet series between the 2 letters in triangle 2 is odd, then each alphabet is changed to their immediate successive alphabet in the alphabetical series else each alphabet is changed to their immediate preceding alphabet in the alphabet series.

3. If the product of two digits in triangle 3 is greater than 15, then increase digits by 1 and take the product else take the sum of two digits.

4. If the difference in the position of alphabets(in English alphabet series) of the two alphabets in triangle 4 is less than 10, then the alphabet exchange their positions to their respective immediate succeeding alphabets in the alphabetical series else alphabets exchange their positions in the triangle.Example:

**What is the sum of the digits of triangle (1) and triangle (3) in the following figure?**

CorrectAnswer –

**4) 43**

Solution:

According to given conditions:

In triangle 1:

Sum of digits = 9 + 0 = 9.

Sum of digits < 10 it implies increase each digit by 2 and take the sum. 9 + 2 = 11, 0 + 2 = 2 → Sum of 11 + 2 = 13In triangle 2: Number of letters between ‘d’ and ‘m’ = 8. Number of letters is even. It implies change each alphabet to their immediate preceding alphabet. ‘d’ → ‘c’ and ‘m’ → ‘l’In triangle 3: Product of 4 and 5 = 4 × 5 = 20 Product of two digits > 15 it implies increase each digit by 1 and take the product.

4 + 1 = 5, 5 + 1 = 6 → Product of 5 × 6 = 30In triangle 4:

Difference in position of alphabets ‘f’(6) and ‘o’(15) is 15 – 6 = 9

Difference in position of alphabets < 10 it implies exchange the position of alphabets to their respective immediate succeeding alphabets. ‘f’ → ‘g’ and ‘o’ → ‘p’Sum of the digits of triangle (1) and (3) = 13 + 30 = 43IncorrectAnswer –

**4) 43**

Solution:

According to given conditions:

In triangle 1:

Sum of digits = 9 + 0 = 9.

Sum of digits < 10 it implies increase each digit by 2 and take the sum. 9 + 2 = 11, 0 + 2 = 2 → Sum of 11 + 2 = 13In triangle 2: Number of letters between ‘d’ and ‘m’ = 8. Number of letters is even. It implies change each alphabet to their immediate preceding alphabet. ‘d’ → ‘c’ and ‘m’ → ‘l’In triangle 3: Product of 4 and 5 = 4 × 5 = 20 Product of two digits > 15 it implies increase each digit by 1 and take the product.

4 + 1 = 5, 5 + 1 = 6 → Product of 5 × 6 = 30In triangle 4:

Difference in position of alphabets ‘f’(6) and ‘o’(15) is 15 – 6 = 9

Difference in position of alphabets < 10 it implies exchange the position of alphabets to their respective immediate succeeding alphabets. ‘f’ → ‘g’ and ‘o’ → ‘p’Sum of the digits of triangle (1) and (3) = 13 + 30 = 43 - Question 3 of 10
##### 3. Question

1 pointsCategory: Reasoning**(Directions 1 – 5): To answer the questions, study the following example based on the corresponding conditions given below it.**1. If the sum of two digits in triangle 1 is less than 10, then increase each digits by 2 and then take the sum else decrease the digits by 2 and then take the product.

2. If the number of alphabets in English alphabet series between the 2 letters in triangle 2 is odd, then each alphabet is changed to their immediate successive alphabet in the alphabetical series else each alphabet is changed to their immediate preceding alphabet in the alphabet series.

3. If the product of two digits in triangle 3 is greater than 15, then increase digits by 1 and take the product else take the sum of two digits.

4. If the difference in the position of alphabets(in English alphabet series) of the two alphabets in triangle 4 is less than 10, then the alphabet exchange their positions to their respective immediate succeeding alphabets in the alphabetical series else alphabets exchange their positions in the triangle.Example:

**How many meaningful words can be formed with the alphabets of triangle (2) and triangle (4)?**

CorrectAnswer –

**5) None**

Solution:

According to given conditions:

In triangle 1:

Sum of digits = 4 + 8 = 12.

Sum of digits > 10 it implies decrease each digit by 2 and take the product.

4 – 2 = 2, 8 – 2 = 6 → Product of 2 × 6 = 12In triangle 2:

Number of letters between ‘c’ and ‘j’ = 6.

Number of letters is even. It implies change each alphabet to their immediate preceding alphabet.

‘c’ → ‘b’ and ‘j’ → ‘i’In triangle 3:

Product of 7 and 2 = 7 × 2 = 14

Product of two digits < 15 it implies take the sum of two digits. 7 + 2 = 09.In triangle 4: Difference in position of alphabets ‘b’(2) and ‘h’(8) is 8 – 2 = 6 Difference in position of alphabets < 10 it implies exchange the position of alphabets to their respective immediate succeeding alphabets. ‘b’ → ‘c’ and ‘h’ → ‘i’No word is formed by alphabet ‘b’, ‘i’, ‘c’, ‘i’IncorrectAnswer –

**5) None**

Solution:

According to given conditions:

In triangle 1:

Sum of digits = 4 + 8 = 12.

Sum of digits > 10 it implies decrease each digit by 2 and take the product.

4 – 2 = 2, 8 – 2 = 6 → Product of 2 × 6 = 12In triangle 2:

Number of letters between ‘c’ and ‘j’ = 6.

Number of letters is even. It implies change each alphabet to their immediate preceding alphabet.

‘c’ → ‘b’ and ‘j’ → ‘i’In triangle 3:

Product of 7 and 2 = 7 × 2 = 14

Product of two digits < 15 it implies take the sum of two digits. 7 + 2 = 09.In triangle 4: Difference in position of alphabets ‘b’(2) and ‘h’(8) is 8 – 2 = 6 Difference in position of alphabets < 10 it implies exchange the position of alphabets to their respective immediate succeeding alphabets. ‘b’ → ‘c’ and ‘h’ → ‘i’No word is formed by alphabet ‘b’, ‘i’, ‘c’, ‘i’ - Question 4 of 10
##### 4. Question

1 pointsCategory: Reasoning

2. If the number of alphabets in English alphabet series between the 2 letters in triangle 2 is odd, then each alphabet is changed to their immediate successive alphabet in the alphabetical series else each alphabet is changed to their immediate preceding alphabet in the alphabet series.

3. If the product of two digits in triangle 3 is greater than 15, then increase digits by 1 and take the product else take the sum of two digits.

4. If the difference in the position of alphabets(in English alphabet series) of the two alphabets in triangle 4 is less than 10, then the alphabet exchange their positions to their respective immediate succeeding alphabets in the alphabetical series else alphabets exchange their positions in the triangle.Example:

**Find the sum of positions of alphabets in English alphabet series of triangle (2) and triangle (4)?**

CorrectAnswer –

**4) 60**

Solution:

According to given conditions:

In triangle 1:

Sum of digits = 5 + 2 = 7.

Sum of digits < 10 it implies increase each digit by 2 and take the sum. 5 + 2 = 7, 2 + 2 = 4 → Sum of 7 + 4 = 11In triangle 2: Number of letters between ‘a’ and ‘j’ = 8. Number of letters is even. It implies change each alphabet to their immediate preceding alphabet. ‘a’ → ‘z’ and ‘j’ → ‘i’ Position of ‘z’ in English alphabet series = 26 Position of ‘i’ in English alphabet series = 9In triangle 3: Product of 6 and 1 = 6 × 1 = 6 Product of two digits < 15 it implies take the sum of two digits. 6 + 1 = 07.In triangle 4: Difference in position of alphabets ‘g’(7) and ‘p’(16) is 16 – 7 = 9 Difference in position of alphabets < 10 it implies exchange the position of alphabets to their respective immediate succeeding alphabets. ‘g’ → ‘h’ and ‘p’ → ‘q’ Position of ‘h’ in English alphabet series = 8 Position of ‘q’ in English alphabet series = 17 Sum of position of alphabets = 26 + 9 + 8 + 17 = 60IncorrectAnswer –

**4) 60**

Solution:

According to given conditions:

In triangle 1:

Sum of digits = 5 + 2 = 7.

Sum of digits < 10 it implies increase each digit by 2 and take the sum. 5 + 2 = 7, 2 + 2 = 4 → Sum of 7 + 4 = 11In triangle 2: Number of letters between ‘a’ and ‘j’ = 8. Number of letters is even. It implies change each alphabet to their immediate preceding alphabet. ‘a’ → ‘z’ and ‘j’ → ‘i’ Position of ‘z’ in English alphabet series = 26 Position of ‘i’ in English alphabet series = 9In triangle 3: Product of 6 and 1 = 6 × 1 = 6 Product of two digits < 15 it implies take the sum of two digits. 6 + 1 = 07.In triangle 4: Difference in position of alphabets ‘g’(7) and ‘p’(16) is 16 – 7 = 9 Difference in position of alphabets < 10 it implies exchange the position of alphabets to their respective immediate succeeding alphabets. ‘g’ → ‘h’ and ‘p’ → ‘q’ Position of ‘h’ in English alphabet series = 8 Position of ‘q’ in English alphabet series = 17 Sum of position of alphabets = 26 + 9 + 8 + 17 = 60 - Question 5 of 10
##### 5. Question

1 pointsCategory: Reasoning

2. If the number of alphabets in English alphabet series between the 2 letters in triangle 2 is odd, then each alphabet is changed to their immediate successive alphabet in the alphabetical series else each alphabet is changed to their immediate preceding alphabet in the alphabet series.

3. If the product of two digits in triangle 3 is greater than 15, then increase digits by 1 and take the product else take the sum of two digits.

4. If the difference in the position of alphabets(in English alphabet series) of the two alphabets in triangle 4 is less than 10, then the alphabet exchange their positions to their respective immediate succeeding alphabets in the alphabetical series else alphabets exchange their positions in the triangle.Example:

**Find the product of numbers in triangle (1) and triangle (3)?**

CorrectAnswer –

**3) 440**

Solution:

According to given conditions:

In triangle 1:

Sum of digits = 2 + 5 = 7.

Sum of digits < 10 it implies increase each digit by 2 and take the sum. 2 + 2 = 4, 5 + 2 = 7 → Sum of 4 + 7 = 11In triangle 2: Number of letters between ‘k’ and ‘v’ = 10. Number of letters is even. It implies change each alphabet to their immediate preceding alphabet. ‘k’ → ‘j’ and ‘v’ → ‘u’In triangle 3: Product of 3 and 9 = 3 × 9 = 27 Product of two digits > 15 it implies increase each digit by 1 and take the product.

3 + 1 = 4, 9 + 1 = 10 → Product of 4 and 10 = 4 × 10 = 40In triangle 4:

Difference in position of alphabets ‘d’(4) and ‘l’(12) is 12 – 4 = 8

Difference in position of alphabets < 10 it implies exchange the position of alphabets to their respective immediate succeeding alphabets. ‘d’ → ‘e’ and ‘l’ → ‘m’Product of numbers of triangle (1) and triangle (3) = 11 × 40 = 440IncorrectAnswer –

**3) 440**

Solution:

According to given conditions:

In triangle 1:

Sum of digits = 2 + 5 = 7.

Sum of digits < 10 it implies increase each digit by 2 and take the sum. 2 + 2 = 4, 5 + 2 = 7 → Sum of 4 + 7 = 11In triangle 2: Number of letters between ‘k’ and ‘v’ = 10. Number of letters is even. It implies change each alphabet to their immediate preceding alphabet. ‘k’ → ‘j’ and ‘v’ → ‘u’In triangle 3: Product of 3 and 9 = 3 × 9 = 27 Product of two digits > 15 it implies increase each digit by 1 and take the product.

3 + 1 = 4, 9 + 1 = 10 → Product of 4 and 10 = 4 × 10 = 40In triangle 4:

Difference in position of alphabets ‘d’(4) and ‘l’(12) is 12 – 4 = 8

Difference in position of alphabets < 10 it implies exchange the position of alphabets to their respective immediate succeeding alphabets. ‘d’ → ‘e’ and ‘l’ → ‘m’Product of numbers of triangle (1) and triangle (3) = 11 × 40 = 440 - Question 6 of 10
##### 6. Question

1 pointsCategory: Reasoning**(Directions 6 – 10): Study the given information carefully and answer the given questions:**An input-output is given in different steps. Some operations are done in each step. No operation is repeated in next step.

**Input – stqi 11 8 uibh 3 gqrs 7 bsgf**

Step 1 – duig stqi 11 8 uibh gprs 7 6

Step 2 – jsuu duig stqi 11 8 uibh 6 21

Step 3 – wxul jsuu duig uibh 11 6 21 32

Step 4 – zngl wxul jsuu duig 6 21 32 55As per the rules followed in the steps given above, find out in each of the following questions the appropriate steps for the given input.

**Input – hais 12 5 mkld 4 klod 9 cegd****In step IV, which of the following present on the third from left end of the row?**CorrectAnswer –

**5) kdlu**

Solution:

In first step, the word which comes first according to English alphabet dictionary has taken and the smallest number has taken.

bsgf →duig {b + 2 = d, s + 2 = u, g + 2 = i, f + 1 = g} and 3 × 2 = 6

In second step:

gprs → jsuu {g + 3 = j, p + 3 = s, r + 3 = u, s + 2 = u} and 7 × 3 = 21

In third step:

stqi → wxul {s + 4 = w, t + 4 = x, q + 4 = u, i + 3 = l} and 8 × 4 = 32

In fourth step:

uibh → zngl {u + 5 = z, i + 5 = n, b + 5 = g, h + 4 = l} and 11 × 5 = 55Input – hais 12 5 mkld 4 klod 9 cegd

Step I – egie hais 12 5 mkld klod 9 8

Step II – kdlu egie 12 mkld klod 9 8 15

Step 3 – opsg kdlu egie 12 mkld 8 15 36

Step 4 – rpqh opsg kdlu egie 8 15 36 60IncorrectAnswer –

**5) kdlu**

Solution:

In first step, the word which comes first according to English alphabet dictionary has taken and the smallest number has taken.

bsgf →duig {b + 2 = d, s + 2 = u, g + 2 = i, f + 1 = g} and 3 × 2 = 6

In second step:

gprs → jsuu {g + 3 = j, p + 3 = s, r + 3 = u, s + 2 = u} and 7 × 3 = 21

In third step:

stqi → wxul {s + 4 = w, t + 4 = x, q + 4 = u, i + 3 = l} and 8 × 4 = 32

In fourth step:

uibh → zngl {u + 5 = z, i + 5 = n, b + 5 = g, h + 4 = l} and 11 × 5 = 55Input – hais 12 5 mkld 4 klod 9 cegd

Step I – egie hais 12 5 mkld klod 9 8

Step II – kdlu egie 12 mkld klod 9 8 15

Step 3 – opsg kdlu egie 12 mkld 8 15 36

Step 4 – rpqh opsg kdlu egie 8 15 36 60 - Question 7 of 10
##### 7. Question

1 pointsCategory: Reasoning**(Directions 6 – 10): Study the given information carefully and answer the given questions:**An input-output is given in different steps. Some operations are done in each step. No operation is repeated in next step.

**Input – stqi 11 8 uibh 3 gqrs 7 bsgf**

Step 1 – duig stqi 11 8 uibh gprs 7 6

Step 2 – jsuu duig stqi 11 8 uibh 6 21

Step 3 – wxul jsuu duig uibh 11 6 21 32

Step 4 – zngl wxul jsuu duig 6 21 32 55As per the rules followed in the steps given above, find out in each of the following questions the appropriate steps for the given input.

**Input – hais 12 5 mkld 4 klod 9 cegd****In step II, which of the following is present between mkld and 9?**CorrectAnswer –

**4) klod**IncorrectAnswer –

**4) klod** - Question 8 of 10
##### 8. Question

1 pointsCategory: Reasoning**(Directions 6 – 10): Study the given information carefully and answer the given questions:**An input-output is given in different steps. Some operations are done in each step. No operation is repeated in next step.

**Input – stqi 11 8 uibh 3 gqrs 7 bsgf**

Step 1 – duig stqi 11 8 uibh gprs 7 6

Step 2 – jsuu duig stqi 11 8 uibh 6 21

Step 3 – wxul jsuu duig uibh 11 6 21 32

Step 4 – zngl wxul jsuu duig 6 21 32 55As per the rules followed in the steps given above, find out in each of the following questions the appropriate steps for the given input.

**Input – hais 12 5 mkld 4 klod 9 cegd****In step III, if opsg is related to 36, egie is related to 8 then kdlu is related to which of the following number/alphabet?**CorrectAnswer –

**1) 15**IncorrectAnswer –

**1) 15** - Question 9 of 10
##### 9. Question

1 pointsCategory: Reasoning**(Directions 6 – 10): Study the given information carefully and answer the given questions:**

**Input – stqi 11 8 uibh 3 gqrs 7 bsgf**

Step 1 – duig stqi 11 8 uibh gprs 7 6

Step 2 – jsuu duig stqi 11 8 uibh 6 21

Step 3 – wxul jsuu duig uibh 11 6 21 32

Step 4 – zngl wxul jsuu duig 6 21 32 55

**Input – hais 12 5 mkld 4 klod 9 cegd****What is the sum of all the numbers present in step V?**CorrectAnswer –

**4) 119**IncorrectAnswer –

**4) 119** - Question 10 of 10
##### 10. Question

1 pointsCategory: Reasoning**(Directions 6 – 10): Study the given information carefully and answer the given questions:**

**Input – stqi 11 8 uibh 3 gqrs 7 bsgf**

Step 1 – duig stqi 11 8 uibh gprs 7 6

Step 2 – jsuu duig stqi 11 8 uibh 6 21

Step 3 – wxul jsuu duig uibh 11 6 21 32

Step 4 – zngl wxul jsuu duig 6 21 32 55

**Input – hais 12 5 mkld 4 klod 9 cegd****How many numbers/alphabets are present between egie and 9 in step I?**CorrectAnswer –

**4) Five**IncorrectAnswer –

**4) Five**

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