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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeDirections(Q.15) Study the given table and answer the questions given below.
Number of students in five institutes during five years
Number of students in Institute E is increased by what percent from 2013 to 2016?
Correct
Answer – 1) 105%
Explanation:
Required % = 164 – 80 / 80 * 100 = 105%Incorrect
Answer – 1) 105%
Explanation:
Required % = 164 – 80 / 80 * 100 = 105% 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeDirections(Q.15) Study the given table and answer the questions given below.
Number of students in five institutes during five years
Number of students in institutes B and C decreased by 5% and 10% respectively from 2017 to 2018. What was the difference between the total number of students in institutes B and C in 2018?
Correct
Answer – 1) 51
Explanation :
120 * 95/100 = 114
70 * 90/100 = 63
Total number of students = 114 – 63 = 51Incorrect
Answer – 1) 51
Explanation :
120 * 95/100 = 114
70 * 90/100 = 63
Total number of students = 114 – 63 = 51 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeDirections(Q.15) Study the given table and answer the questions given below.
Number of students in five institutes during five years
What is the sum of total number of students in institute A in 2013 and 2014 together and in Institute D in the same years together?
Correct
Answer – 4) 321
Explanation :
Total number of students in institute A in 2013 and 2014 together = 124
Total number of students in institute D in 2013 and 2014 together = 197
sum = 197 + 124 = 321Incorrect
Answer – 4) 321
Explanation :
Total number of students in institute A in 2013 and 2014 together = 124
Total number of students in institute D in 2013 and 2014 together = 197
sum = 197 + 124 = 321 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeDirections(Q.15) Study the given table and answer the questions given below.
Number of students in five institutes during five years
What is the respective ratio between total number of students in institutes B and C together in 2014 and total number of students in institutes D and E together in 2017?
Correct
Answer – 5) 21:23
Explanation :
institutes B and C together in 2014 = 189
institutes D and E together in 2017 = 207
189 : 207 => 21:23Incorrect
Answer – 5) 21:23
Explanation :
institutes B and C together in 2014 = 189
institutes D and E together in 2017 = 207
189 : 207 => 21:23 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeDirections(Q.15) Study the given table and answer the questions given below.
Number of students in five institutes during five years
What is the average number of students in Institutes A, B and E in 2015?
Correct
Answer – 5) 94
Explanation :
Institutes A, B and E in 2015 = (56 + 79 + 147) / 3 = 94Incorrect
Answer – 5) 94
Explanation :
Institutes A, B and E in 2015 = (56 + 79 + 147) / 3 = 94 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeMalini goes to a shop and buys a jewel, costing Rs 5600 including tax of 12%. The shopkeeper gives her a discount, so that the price is decreased by an amount equivalent to tax. The price is decreased by
Correct
Answer – 5) Rs 600
Explanation:
Price of jewel = Rs x
112x/100=5600
x = 5000
Sales tax = Rs.(56005000) = Rs 600 = Amount of discountIncorrect
Answer – 5) Rs 600
Explanation:
Price of jewel = Rs x
112x/100=5600
x = 5000
Sales tax = Rs.(56005000) = Rs 600 = Amount of discount 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeThe marked price(MP) of a Book is 40% less than that of magazine. The discount on the Book is 50%. What should be the discount on the magazine so that the overall discount on the magazine and the Book taken together is 37.5%
Correct
Answer – 4) 30%
Explanation:
40 % = 2/5
Let the price of magazine be 5X , so price of Book =3x
Discount on magazine = {(75 * 8X)/2*100}{(50 *3X)/100}=1.5X
So % discount on magazine = (1.5X *100)/5X= 30%Incorrect
Answer – 4) 30%
Explanation:
40 % = 2/5
Let the price of magazine be 5X , so price of Book =3x
Discount on magazine = {(75 * 8X)/2*100}{(50 *3X)/100}=1.5X
So % discount on magazine = (1.5X *100)/5X= 30% 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeThe ratio of work done by 20 men to work done by 30 children in same time is 8:5. If 10 men and 18 children can do a work in 12 days, then how many men would be required to finish it in 7 days.
Correct
Answer – 1) 30
Explanation:
20 M x 5 = 30 C x 8
10 men = 24 children
5 men = 12 children
10 men + 18 children = 24+18 = 42 children
Number of children required to finish the work in 7 days = (42×12)/7=72 children
72 children = 30 menIncorrect
Answer – 1) 30
Explanation:
20 M x 5 = 30 C x 8
10 men = 24 children
5 men = 12 children
10 men + 18 children = 24+18 = 42 children
Number of children required to finish the work in 7 days = (42×12)/7=72 children
72 children = 30 men 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeRanjith’s age after 17 years will be 6 years less than twice his present age. The respective ratio between Vivek’s present age and Anil’s present age is 21 : 19. If Anil’s age 31 years hence will be same as three times Ranjith’s present age. what will be Vivek’s age 6 years hence.
Correct
Answer – 4) 48
Explanation:
Let Ranjith’s present age = X years
So X+17= 2X6
X=23 years
Vivek’s present age = 21Y
Anil’s present age = 19Y
19Y + 31 = 3 * 23
Y=2 years
Vivek’s age 6 years hence = (21*2)+6 = 48 yearsIncorrect
Answer – 4) 48
Explanation:
Let Ranjith’s present age = X years
So X+17= 2X6
X=23 years
Vivek’s present age = 21Y
Anil’s present age = 19Y
19Y + 31 = 3 * 23
Y=2 years
Vivek’s age 6 years hence = (21*2)+6 = 48 years 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeA sum of money was invested for “X” years in scheme P offering SI. The amount received after “X” years was twice the sum of money invested in the scheme. What will be the amount received for scheme P, when a sum of Rs 6400, is invested for “2X” years.
Correct
Answer – 1) 19200
Explanation:
A * 100 =P(100 + RX)
2P * 100= P(100 + RX)
R= 100/X
A *100= P(100+RX)
A *100=6400 {100 + 100/x *2x)}
A = 19200Incorrect
Answer – 1) 19200
Explanation:
A * 100 =P(100 + RX)
2P * 100= P(100 + RX)
R= 100/X
A *100= P(100+RX)
A *100=6400 {100 + 100/x *2x)}
A = 19200
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