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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeDirections for Questions 15: Study the following charts and answer the questions that follow:
Find the price per unit of Brand A?
Correct
Solution: The price per unit of Brand A: (0.25*2250*10^7)/ (0.16*13500* 10^6) = 562.5/216 = 2.6.
Incorrect
Solution: The price per unit of Brand A: (0.25*2250*10^7)/ (0.16*13500* 10^6) = 562.5/216 = 2.6.

Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeDirections for Questions 15: Study the following charts and answer the questions that follow:
The costliest brand of Cold Drinks in 2007 for the company ABC Ltd. was priced at:
Correct
Solution: The price per unit of Brand A: (0.25*2250*10^7)/ (0.16*13500* 10^6) = 562.5/216 = 2.6. Price per unit of brand B = (0.13*2250)/ (0.14*1350) = 1.55. Similarly price per units of Brand C, D, E and F are Rs. 1.23, Rs. 2.22, Rs. 2.5 and Rs. 0.8333 respectively. Hence brand A is the costliest which is Rs. 2.6 per bottle.
Incorrect
Solution: The price per unit of Brand A: (0.25*2250*10^7)/ (0.16*13500* 10^6) = 562.5/216 = 2.6. Price per unit of brand B = (0.13*2250)/ (0.14*1350) = 1.55. Similarly price per units of Brand C, D, E and F are Rs. 1.23, Rs. 2.22, Rs. 2.5 and Rs. 0.8333 respectively. Hence brand A is the costliest which is Rs. 2.6 per bottle.

Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeDirections for Questions 15: Study the following charts and answer the questions that follow:
Find the ratio of prices of the cheapest brand to the costliest brand for the company in 2007.
Correct
Solution: The cheapest brand cost Rs. 5/6 = 8.333 and the costliest brand’s price is Rs 125/48=2.6. Hence the required price ratio is 5/6: 125/48 = 8:25
Incorrect
Solution: The cheapest brand cost Rs. 5/6 = 8.333 and the costliest brand’s price is Rs 125/48=2.6. Hence the required price ratio is 5/6: 125/48 = 8:25

Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeDirections for Questions 15: Study the following charts and answer the questions that follow:
If the manufacturing cost of a Cold Drink of Brand C was 93 paisa per bottle then what was the total profit of the company for the brand C?
Correct
Solution: The profit for one bottle of brand C is 1.23 0.93 = 0.3. Hence the total profit of brand C = 0.3*0.27*13500*10^6= 109.35 crore
Incorrect
Solution: The profit for one bottle of brand C is 1.23 0.93 = 0.3. Hence the total profit of brand C = 0.3*0.27*13500*10^6= 109.35 crore

Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeDirections for Questions 15: Study the following charts and answer the questions that follow:
Say the consumers of brand E change over to brand A and D in the ratio of 2:3 respectively because brand E suffered A loss and withdrew from the market then what will be the new percentage share of brand A in the value sales?
Correct
Solution: Percentage share of brand A in value sales = 25 + (2/5*12) = 30%
Incorrect
Solution: Percentage share of brand A in value sales = 25 + (2/5*12) = 30%

Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeDirection for Question 68: In the following question, two statements are numbered as I and II. On solving these statements you get Quantity I and Quantity II respectively. Solve for both the statements individually and mark the correct answer.
Quantity I: 1. A is 2 1⁄3 times as fast as B. If A gives B a start of 80 m, how long should the race course be so that both of them reach at the same time?
Quantity II: Two boys A and B run at 4 1⁄5 and 8 km an hour respectively. A having 150 m start and the course being 1 km, B wins by a distance of?Correct
Solution: Quantity I, Speed of A : Speed of B = 7⁄3 : 1 = 7 : 3,It means, in a race of 7 m, A gains (73)=4 metre, If A needs to gain 80 metre, race should be of 7/4×80 = 140 metre. Quantity II, has a start of 150 m. So A has to run 1000150=850 metre while B has to run 1000 metre. Speed of A = 4 1/5 km/hr =21/5 km/hr =21/5×5/18 =21/18 =7/6 m/s, Speed of B = 8 km/hour = 8×5/18=20/9 m/s, Time taken by B to travel 1000 metre = distance/Speed of B=1000/(20/9)= 450 second. Distance travelled by A by this time = time × speed of A = 450×7/6=525 metre. Hence, A win by 850525=325 metre. Hence, Quantity I < Quantity II
Incorrect
Solution: Quantity I, Speed of A : Speed of B = 7⁄3 : 1 = 7 : 3,It means, in a race of 7 m, A gains (73)=4 metre, If A needs to gain 80 metre, race should be of 7/4×80 = 140 metre. Quantity II, has a start of 150 m. So A has to run 1000150=850 metre while B has to run 1000 metre. Speed of A = 4 1/5 km/hr =21/5 km/hr =21/5×5/18 =21/18 =7/6 m/s, Speed of B = 8 km/hour = 8×5/18=20/9 m/s, Time taken by B to travel 1000 metre = distance/Speed of B=1000/(20/9)= 450 second. Distance travelled by A by this time = time × speed of A = 450×7/6=525 metre. Hence, A win by 850525=325 metre. Hence, Quantity I < Quantity II

Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeDirection for Question 68: In the following question, two statements are numbered as I and II. On solving these statements you get Quantity I and Quantity II respectively. Solve for both the statements individually and mark the correct answer.
Quantity I: A and B started a partnership business investing Rs. 20,000 and Rs. 15,000 respectively. C joined them with Rs. 20,000 after six months. Calculate B’s share in total profit of Rs. 25,000 earned at the end of 2 years from the starting of the business?
Quantity II: A, B and C jointly thought of engaging themselves in a business venture. It was agreed that A would invest Rs. 6500 for 6 months, B, Rs. 8400 for 5 months and C, Rs. 10,000 for 3 months. A wants to be the working member for which, he was to receive 5% of the profits. The profit earned was Rs. 7400. What is the share of B in the profit?
Correct
Solution: Quantity I A : B : C
=20000×24:15000×24:20000×18=20×4:15×4:20×3=4×4:3×4:4×3=4:3:3B’s share = 25000×3/10=7500. Quantity II : A is a working member and for that, he receives 5% of the profit = 5% of 7400 =5×7400/100=370. Remaining amount =7400−370=7030, Ratio of their investments =6500×6:8400×5:10000×3= 65×6:84×5:100×3= 13×6:84:20×3= 13×2:28:20= 13:14:10
Share of B in the profit=7030×14/37=190×14=2660. Hence, Quantity I > Quantity IIIncorrect
Solution: Quantity I A : B : C
=20000×24:15000×24:20000×18=20×4:15×4:20×3=4×4:3×4:4×3=4:3:3B’s share = 25000×3/10=7500. Quantity II : A is a working member and for that, he receives 5% of the profit = 5% of 7400 =5×7400/100=370. Remaining amount =7400−370=7030, Ratio of their investments =6500×6:8400×5:10000×3= 65×6:84×5:100×3= 13×6:84:20×3= 13×2:28:20= 13:14:10
Share of B in the profit=7030×14/37=190×14=2660. Hence, Quantity I > Quantity II 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeDirection for Question 68: In the following question, two statements are numbered as I and II. On solving these statements you get Quantity I and Quantity II respectively. Solve for both the statements individually and mark the correct answer.
Quantity I: A housewife saved Rs. 2.50 in buying an item on sale. If she spent Rs. 25 for the item, approximately how much percent she saved in the transaction ?
Quantity II If the price of petrol increases by 25% and Benson intends to spend only an additional 15% on petrol, by how much percent will he reduce the quantity of petrol purchased?Correct
Solution: Actual price = Rs.25 + Rs.2.50 = Rs.27.5, Saving = Rs.2.5, Saving percent=2.5/27.5×100 =250/27.5= 2500/275=100/11=9 1/11% ≈ 9% . Quantity II: Assume that initial price of 1 litre petrol = Rs.100,Benson spends Rs.100 for petrol such that he buys 1 litre of petrol. After the increase by 25%, price of 1 litre petrol
=100+25=125. Since Benson spends additional 15% on petrol, amount spent by him
=100+15=115. Hence quantity of petrol that he can purchase =115/125 litre. Quantity of petrol reduced =(1−115/125)=10/125 litre
Required reduction percent=(10/125)/1×100= 10/125×100=10/5×4=2×4=8%. Hence, Quantity I > Quantity IIIncorrect
Solution: Actual price = Rs.25 + Rs.2.50 = Rs.27.5, Saving = Rs.2.5, Saving percent=2.5/27.5×100 =250/27.5= 2500/275=100/11=9 1/11% ≈ 9% . Quantity II: Assume that initial price of 1 litre petrol = Rs.100,Benson spends Rs.100 for petrol such that he buys 1 litre of petrol. After the increase by 25%, price of 1 litre petrol
=100+25=125. Since Benson spends additional 15% on petrol, amount spent by him
=100+15=115. Hence quantity of petrol that he can purchase =115/125 litre. Quantity of petrol reduced =(1−115/125)=10/125 litre
Required reduction percent=(10/125)/1×100= 10/125×100=10/5×4=2×4=8%. Hence, Quantity I > Quantity II 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeSandeep’s age after six years will be threeseventh of his father’s age. Ten years ago the ratio of their ages was 1:5. What is Sandeep’s father’s age at present?
Correct
Solution: Let the age of Sandeep and his father before 1010 years be x and 5x respectively. Given that Sandeep’s age after six years will be threeseventh of his father’s age ⇒x+16=3/7(5x+16) ⇒7x+112=15x+48 ⇒8x=64 ⇒x=8Sandeep’s father’s present age =5x+10=5×8+10=50
Incorrect
Solution: Let the age of Sandeep and his father before 1010 years be x and 5x respectively. Given that Sandeep’s age after six years will be threeseventh of his father’s age ⇒x+16=3/7(5x+16) ⇒7x+112=15x+48 ⇒8x=64 ⇒x=8Sandeep’s father’s present age =5x+10=5×8+10=50

Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeThe base of a parallelogram is (p+4), altitude to the base is (p−3) and the area is (p2−4),find out its actual area.
Correct
Solution: Area of a parallelogram, A =bh, Hence, we have p2−4= (p+4)(p−3)⇒p2−4=p2+p−12⇒−4=p−12⇒p=12−4=8. Hence, actual area =(p2−4)
=82−4=64−4=60sq. unitsIncorrect
Solution: Area of a parallelogram, A =bh, Hence, we have p2−4= (p+4)(p−3)⇒p2−4=p2+p−12⇒−4=p−12⇒p=12−4=8. Hence, actual area =(p2−4)
=82−4=64−4=60sq. units
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