IBPS PO 2017 Practice Test – Quant Day 20

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Q(1-5). Study the given table and answer the following questions.

Note: HRA = % of Basic Pay DA = % of Basic Pay
Gross Salary = Basic Pay +HRA+DA+TA
Total Allowances = HRA+DA+TA
NPS = % of Basic Pay
In Hand Salary = Gross Salary – NPS – CGHS

1. Who among the following received highest In Hand salary?
   A. Sanjay
   B. Sriram
   C. Srikanth
   D. Sushanth
   E. Sujith
   
   Answer & Explanation

   C. Srikanth
   Solution:
   Sanjay:
   In Hand Salary : 437*120+1123-652 = 52911
   Sriram:
   In Hand Salary : 442*117+1191-423 = 52482
   Srikanth
   In Hand Salary : 429*123+1176– 999 = 52944
   Sushant
   In Hand Salary: 431*120+1214-502 = 52432
   Sujith:
   In Hand Salary: 434*118+1185-416 = 51981
   
   
2. What is the difference between In Hand salaries of who got the Highest salary and the one who got the least salary?
   A. 963
   B. 1063
   C. 1073
   D. 1163
   E. None
   
   Answer & Explanation

   A. 963
   Solution:
   Srikanth:
   In Hand Salary : 52944
   Sujith:
   In Hand Salary: 51981
   Difference = 52944-51981 = 963
   
   
3. Difference between Gross Salary and In Hand Salary of which of the employees is minimum?
   A. Sanjay
   B. Sriram
   C. Srikanth
   D. Sushanth
   E. Sujith
   
   Answer & Explanation

   E. Sujith
   Solution:
   Sanjay : 437*131 +1123 = 58370
   58370-52911 = 5459
   Srirram: 57767-52482 = 5285
   Srikanth: 58762-53044 = 5718
   Sushant: 57675- 52432 = 5243
   Sujith: 57171-51981 = 5190
   
   
4. Who among the following received maximum Total Allowances?
   A. Sanjay
   B. Sriram
   C. Srikanth
   D. Sushanth
   E. Sujith
   
   Answer & Explanation

   C. Srikanth
   Solution:
   By observation Srikanth: 9867+4719+1176 = 15762
   
   
5. If HRA of all employees is fixed at 20% then who among the following will receive least In Hand Salary?
   A. Sanjay
   B. Sriram
   C. Srikanth
   D. Sushanth
   E. Sujith
   
   Answer & Explanation

   C. Srikanth
   Solution:
   Sanjay: 52911-9614+8740 = 52037
   Sriram: 52482 – 8840+8840 = 52482
   Srikanth: 53044- 9807+8580 = 51757
   Sushanth: 52432- 9051+8620 = 52001
   Sujith: 51981- 8680+ 8680 = 51981
   
   

Q(6-10). Study the following Line Graph which represents total no of cars and given table contains ratio of Cars.

6. In which of the following City Maximum no of Electrical cars are present?
   A. Indore
   B. Bhopal
   C. Ujjian
   D. Satna
   E. Rewa
   
   Answer & Explanation

   E. Rewa
   Solution:
   Indore: 492*3/12 = 123
   Bhopal: 510*4/15 = 136
   Ujjain: 492*1/6 = 82
   Satna: 513*2/9 = 114
   Rewa: 504*5/18 = 140
   
   
7. What is the ratio of total No of Petrol and Diesel cars in Ujjain to total No of Petrol and Diesel cars in Satna?
   A. 411:399
   B. 410:399
   C. 411:400
   D. 413:399
   E. None
   
   Answer & Explanation

   B. 410:399
   Solution:
   492*5/6 : 513*7/9
   410:399
   
   
8. What is the difference between Petrol and Diesel cars in all cities together?
   A. 62
   B. 66
   C. 68
   D. 72
   E. None
   
   Answer & Explanation

   D. 72
   Solution:
   1/12*492 + 1/15*510 + 1/6*492 – 1/9*513 – 1/18* 504 = 72
   
   
9. Total Petrol cars in all cities form approximately what percent of the total no of cars in all cities together?
   A. 25%
   B. 35%
   C. 40%
   D. 45%
   E. 50%
   
   Answer & Explanation

   C. 40%
   Solution:
   Petrol cars = 205+204+246+171+168 = 994
   Total Cars = 492+510+492+513+504 = 2511
   % = 994/2511*100
   
   
10. If the pollution level in the cities is based on percentage usage of cars i.e., higher the percentage use of electrical cars lower the pollution. Then which of the following city is least polluted?
    A. Indore
    B. Bhopal
    C. Ujjain
    D. Satna
    E. Rewa
    
    Answer & Explanation

    E. Rewa
    Solution:
    % usage of electrical cars
    Indore: 123/492*100 = 25%
    Bhopal : 136/510*100 = 26.66%
    Ujjain: 82/492*100 = 16.66%
    Satna: 114/513*100 = 22.22%
    Rewa: 140/504*100 = 27.77%