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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeWhat should come in place of question mark (?) in the following number series?
2 12 36 80 150 (?) 392
Correct
Answer – 3) 252
Explanation:
1^{3} + 1^{2}= 1 + 1= 2
2^{3} + 2^{2}= 8 + 4= 12
3^{3} + 3^{2}= 27 + 9= 36
4^{3} + 4^{2}= 64 + 16= 80
5^{3} + 5^{2} =125 + 25= 150
6^{3} + 6^{2} =216 + 36= 252
7^{3} + 7^{2}= 343 + 49= 392Incorrect
Answer – 3) 252
Explanation:
1^{3} + 1^{2}= 1 + 1= 2
2^{3} + 2^{2}= 8 + 4= 12
3^{3} + 3^{2}= 27 + 9= 36
4^{3} + 4^{2}= 64 + 16= 80
5^{3} + 5^{2} =125 + 25= 150
6^{3} + 6^{2} =216 + 36= 252
7^{3} + 7^{2}= 343 + 49= 392 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeWhat should come in place of question mark (?) in the following number series?
1021 503 229 (?) 179 697Correct
Answer – 2) 47
Explanation:
2^{10} – 3^{1} = 1024 – 3= 1021
2^{9} – 3^{2} = 512 – 9 = 503
2^{8 }– 3^{3} = 256 – 27 = 229
2^{7} – 3^{4} = 128 – 81 = 47
2^{6 }– 3^{5} = 64 – 243 = 179
2^{5} – 3^{6} = 32 – 729 = – 697Incorrect
Answer – 2) 47
Explanation:
2^{10} – 3^{1} = 1024 – 3= 1021
2^{9} – 3^{2} = 512 – 9 = 503
2^{8 }– 3^{3} = 256 – 27 = 229
2^{7} – 3^{4} = 128 – 81 = 47
2^{6 }– 3^{5} = 64 – 243 = 179
2^{5} – 3^{6} = 32 – 729 = – 697 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeThe cost price of two dozen bananas is Rs 32. After selling 18 bananas at the rate of Rs 12 per dozen, the shopkeeper reduced to rate as Rs 4 per dozen. Find the loss percentage?
Correct
Answer – 4) 37.5%
Explanation:
According to questions,
CP of 2 dozen bananas (24 bananas) = Rs 32
SP of 1 dozen bananas (12 bananas) = Rs 12
SP of 18 bananas= Rs 18
Therefore, Now shopkeeper reduced to the rate Rs 4 per dozen.
Now SP of 1 dozen bananas= Rs 4
SP of 6 bananas= Rs 2
Therefore, SP of 24 bananas = Rs 18 + Rs 2= Rs 20
Loss = CP – SP
32 – 20 = Rs 12
Loss % = (12/32) * 100= 37.5%Incorrect
Answer – 4) 37.5%
Explanation:
According to questions,
CP of 2 dozen bananas (24 bananas) = Rs 32
SP of 1 dozen bananas (12 bananas) = Rs 12
SP of 18 bananas= Rs 18
Therefore, Now shopkeeper reduced to the rate Rs 4 per dozen.
Now SP of 1 dozen bananas= Rs 4
SP of 6 bananas= Rs 2
Therefore, SP of 24 bananas = Rs 18 + Rs 2= Rs 20
Loss = CP – SP
32 – 20 = Rs 12
Loss % = (12/32) * 100= 37.5% 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeA motor boat covers a certain distance downstream in a river is 3 hours. It covers the same distance upstream in 3 hours and half. If the speed of the water is 1.5 Km/hr. Then find the speed of the boat in still water?
Correct
Answer 3) 19.5 km/hr
Explanation:
Downstream Speed (x + y) = 3(x + y)
Upstream Speed (x – y) = 7/2 (x y)
Compare both the distance
3 (x + y) = 7/2 (x – y)
6x + 6y = 7x – 7y
X = 13y
Hence, y= Speed of current = 1.5 Km/hr
X= 13 * 1.5
X (Speed of boat in still water)= 19.5 Km/hrIncorrect
Answer 3) 19.5 km/hr
Explanation:
Downstream Speed (x + y) = 3(x + y)
Upstream Speed (x – y) = 7/2 (x y)
Compare both the distance
3 (x + y) = 7/2 (x – y)
6x + 6y = 7x – 7y
X = 13y
Hence, y= Speed of current = 1.5 Km/hr
X= 13 * 1.5
X (Speed of boat in still water)= 19.5 Km/hr 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeA is twice as good a workman as B and B is twice as good a workman as C. If A and B can together finish a piece of work in 4 days. Then find the number of days in which C can do it by himself?
Correct
Answer –5) 24 days
Explanation:
According to question,
Incorrect
Answer –5) 24 days
Explanation:
According to question,

Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeThese questions are based on the following table which gives the sales of computer peripheral manufactures in India from the year 200102 to the year 200506.
SALES OF COMPUTER PERIPHERAL MANUFACTURERS IN INDIA (in lakhs)
During the given period which company recorded the maximum increase in sales over any two consecutive years?
Correct
Answer –1)P.G
Explanation
By observation P.G shows the maximum increase from 200405 to 200506
(69884857 = 2131).The next maximum increase was recorded by PERCURY which is less than 2100 (from 200304 to 200405)Incorrect
Answer –1)P.G
Explanation
By observation P.G shows the maximum increase from 200405 to 200506
(69884857 = 2131).The next maximum increase was recorded by PERCURY which is less than 2100 (from 200304 to 200405) 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeThese questions are based on the following table which gives the sales of computer peripheral manufactures in India from the year 200102 to the year 200506.
SALES OF COMPUTER PERIPHERAL MANUFACTURERS IN INDIA (in lakhs)
What is the approximate share of the sales of SANSUNG in the year 200304, when compared to the total sales of SANSUNG for the given five years?
Correct
Answer – 2) 18.72 %
Explanation
Sales SANSUNG in 200304 = 5843
Total sales of SANSUNG for all the given five years
= 5046+6395+5843+6814+7122 = 31220
Req. percentage = 5843/31220 x 100
= 18.72 %Incorrect
Answer – 2) 18.72 %
Explanation
Sales SANSUNG in 200304 = 5843
Total sales of SANSUNG for all the given five years
= 5046+6395+5843+6814+7122 = 31220
Req. percentage = 5843/31220 x 100
= 18.72 % 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeThese questions are based on the following table which gives the sales of computer peripheral manufactures in India from the year 200102 to the year 200506.
SALES OF COMPUTER PERIPHERAL MANUFACTURERS IN INDIA (in lakhs)
How many companies showed a consistent trend in sales (i.e. a continuous increase or decrease in sales) during the period 200102 to 200506?
Correct
Answer – 3) 3
Explanation
By observation we can see that MBALL, SINTEX and PERCURY showed a consistent trend (increase) in their sales.Incorrect
Answer – 3) 3
Explanation
By observation we can see that MBALL, SINTEX and PERCURY showed a consistent trend (increase) in their sales. 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeThese questions are based on the following table which gives the sales of computer peripheral manufactures in India from the year 200102 to the year 200506.
SALES OF COMPUTER PERIPHERAL MANUFACTURERS IN INDIA (in lakhs)
What is the average annual growth rate in the sales of PERCURY from 200102 to 200506?
Correct
Answer –4) 19.23 %
Explanation
Total growth rate of PERCURY
From 200102 to 200506 = 66953784 / 3784 = 76.92 %
The average annual growth rate = 76.92 / 51 = 19.23 %Incorrect
Answer –4) 19.23 %
Explanation
Total growth rate of PERCURY
From 200102 to 200506 = 66953784 / 3784 = 76.92 %
The average annual growth rate = 76.92 / 51 = 19.23 % 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeYou have to solve these equations and find out the values of x and y.
17x^{2} +48x = 9
13y^{2} = 32y 12Correct
Answer – 1) x<y
Explanation
17x^{2} +48x = 9
X = 3, 3/1713y^{2} = 32y 12
Y = 2, 6/13Incorrect
Answer – 1) x<y
Explanation
17x^{2} +48x = 9
X = 3, 3/1713y^{2} = 32y 12
Y = 2, 6/13
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