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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeStudy the following graph given below and answer the questions given below.
In which of the following year was the amount of profit maximum?
Correct
Answer –5) None of these
Explanation
For the year 1993, expenditure
= Income/ 100 + profit% x 100
=120/(100+7.5) x 100 = 111.63
Profit = Income – expenditure = 120 – 111.63
=8.37 lakh
Similarly
For the year 1994 profit = 20.86 lakh
For the year 1995 profit = 23.87 lakh
For the year 1996 profit = 25.32 lakh
For the year 1997 profit = 31.67 lakh
For the year 1998 profit = 32.35 lakh
The amount of profit is maximum for the year 1998.Incorrect
Answer –5) None of these
Explanation
For the year 1993, expenditure
= Income/ 100 + profit% x 100
=120/(100+7.5) x 100 = 111.63
Profit = Income – expenditure = 120 – 111.63
=8.37 lakh
Similarly
For the year 1994 profit = 20.86 lakh
For the year 1995 profit = 23.87 lakh
For the year 1996 profit = 25.32 lakh
For the year 1997 profit = 31.67 lakh
For the year 1998 profit = 32.35 lakh
The amount of profit is maximum for the year 1998. 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeStudy the following graph given below and answer the questions given below.
Approximately what was the average expenditure of the given years?
Correct
Answer – 2) Rs 130 Lakh
Explanation
Total Expenditure
=( 120/107.5 +160/115 + 130/112.5 + 170/117.5 + 190/120 + 150/127.5) x 100
=111.62 + 139.12 + 106.12 + 144.68 + 158.33 + 117.64
=777.51
Avg Expenditure = 777.51/6 = 130 LakhIncorrect
Answer – 2) Rs 130 Lakh
Explanation
Total Expenditure
=( 120/107.5 +160/115 + 130/112.5 + 170/117.5 + 190/120 + 150/127.5) x 100
=111.62 + 139.12 + 106.12 + 144.68 + 158.33 + 117.64
=777.51
Avg Expenditure = 777.51/6 = 130 Lakh 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeStudy the following graph given below and answer the questions given below.
In which of the following years was the increase/decrease in percent profit from the previous year was maximum?
Correct
Answer – 1) 1994
Explanation
For the year 1994, increase in profit percentage
=157.5/7.5 x 100 = 100%(maximum)
Similarly for the year 1995 = 50%
1996 =22.22%
1997 =14.28%
1998 = 37.5%Incorrect
Answer – 1) 1994
Explanation
For the year 1994, increase in profit percentage
=157.5/7.5 x 100 = 100%(maximum)
Similarly for the year 1995 = 50%
1996 =22.22%
1997 =14.28%
1998 = 37.5% 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeStudy the following graph given below and answer the questions given below.
Approximately what was the expenditure in 1994?
Correct
Answer – 3) 140 lakh
Explanation
Expenditure in 1994 = 160 / 115 x 100
= 140 lakh (approx)Incorrect
Answer – 3) 140 lakh
Explanation
Expenditure in 1994 = 160 / 115 x 100
= 140 lakh (approx) 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeFind the missing number in the given series?
9, 31, 73, 141, ______Correct
Answer – 4) 241
Explanation
2^{3} + 1^{2} = 9
3^{3} + 2^{2} = 31
4^{3} + 3^{2} = 73
5^{3} + 4^{2} = 131
6^{3} + 5^{2} = 241Incorrect
Answer – 4) 241
Explanation
2^{3} + 1^{2} = 9
3^{3} + 2^{2} = 31
4^{3} + 3^{2} = 73
5^{3} + 4^{2} = 131
6^{3} + 5^{2} = 241 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeIdentify the wrong number in the given series?
144, 215, 540, 1890, 8505, 46777.5, 304053.75Correct
Answer – 1) 215
Explanation
144 x 1.5 = 216
216 x 2.5 = 540
540 x 3.5 = 1890
1890 x 4.5 = 8505
And so onIncorrect
Answer – 1) 215
Explanation
144 x 1.5 = 216
216 x 2.5 = 540
540 x 3.5 = 1890
1890 x 4.5 = 8505
And so on 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeA, B and C started a business with their investments in the ratio 1:2:4. After 6 month A invested the half amount more as before and B invested same the amount as before while C withdrew 1/4th of their investments. Find the ratio of their profits at the end of the year?
Correct
Answer 3) 5:12:14
Explanation
Incorrect
Answer 3) 5:12:14
Explanation

Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeIn measuring the sides of a rectangle, there is an excess of 5% on one side and 2% deficit on the other. What is the error percent in the area?
Correct
Answer – 5) 2.9%
Explanation
Incorrect
Answer – 5) 2.9%
Explanation

Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeA train 150m long passes a Km stone in 30 seconds and another train of the same length travelling in opposite direction in 10 seconds. Find the speed of the second train?
Correct
Answer – 1) 90 Km/hr
Explanation
The length of first train= 150 meter
Length of second train= 150 meter
Speed of first train= 150 m/ 30 s= 5m/s
Speed of second train= S_{2}
Case 2
10 = (150 + 150)/ (S_{2} + 5)
10= 300/ (S_{2} + 5)
1= 30/ (S_{2} + 5)
S_{2}= 25 m/s
Speed of second train= 25 m/s
= 25 * (18/5) Km/hr
= 90 Km/hrIncorrect
Answer – 1) 90 Km/hr
Explanation
The length of first train= 150 meter
Length of second train= 150 meter
Speed of first train= 150 m/ 30 s= 5m/s
Speed of second train= S_{2}
Case 2
10 = (150 + 150)/ (S_{2} + 5)
10= 300/ (S_{2} + 5)
1= 30/ (S_{2} + 5)
S_{2}= 25 m/s
Speed of second train= 25 m/s
= 25 * (18/5) Km/hr
= 90 Km/hr 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeTwelve applications apply for a job of which 5 are women and 7 are men. It is desired to select 3 persons for the job. What is the probability that at least one of the selected people is a woman?
Correct
Answer – 5) 37/44
Explanation
Total number of ways in which 3 persons can be selected out of 12 persons= ^{12}C_{3}
Number of ways at least one women= (^{5}C_{1} X ^{7}C_{2}) + (^{5}C_{2} X ^{7}C_{1}) + ^{5}C_{3}
= 105 + 70 + 10
= 185
Total number of outcomes= ^{12}C_{3}
=220
Probability= 185/220
= 37/44Incorrect
Answer – 5) 37/44
Explanation
Total number of ways in which 3 persons can be selected out of 12 persons= ^{12}C_{3}
Number of ways at least one women= (^{5}C_{1} X ^{7}C_{2}) + (^{5}C_{2} X ^{7}C_{1}) + ^{5}C_{3}
= 105 + 70 + 10
= 185
Total number of outcomes= ^{12}C_{3}
=220
Probability= 185/220
= 37/44
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