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- Question 1 of 10
##### 1. Question

1 pointsCategory: Quantitative Aptitude**The population of a town is 3,11,250. The ratio of women to men is 43:40. If there are 24% literate among women and 10% illiterate among men. Find the total number of literate persons in the town?**CorrectAnswer –

**2) 1, 73, 700**

Explanation:

Population of town= 3, 11, 250

Number of women in town= (311250 / (43 + 40)) * 43

= 161250

Number of literate women= 161250 * (24/100)

= 38700

Number of men in town= (311250 / (43 + 40)) * 40

= 150000

Number of literate men in town= 150000 * ((100 – 10) / 100)

= 135000

Total literate persons in town= 38700 + 135000

= 173700IncorrectAnswer –

**2) 1, 73, 700**

Explanation:

Population of town= 3, 11, 250

Number of women in town= (311250 / (43 + 40)) * 43

= 161250

Number of literate women= 161250 * (24/100)

= 38700

Number of men in town= (311250 / (43 + 40)) * 40

= 150000

Number of literate men in town= 150000 * ((100 – 10) / 100)

= 135000

Total literate persons in town= 38700 + 135000

= 173700 - Question 2 of 10
##### 2. Question

1 pointsCategory: Quantitative Aptitude**Diameter of a wheel is 3 meter. The wheel revolves 28 times in a minute. To cover 5.280 Km distance, the wheel will take how much time?**CorrectAnswer –

**2) 20 minutes**

Explanation:

Diameter of the wheel= 3m

Circumference= ∏ * diameter

= (22/7) * 3

= 66/7

Since a wheel covers a distance equal to its circumference in one revolution therefore distance covered in 28 revolutions= 28 * (66/7)

= 264m

264 meters covered= 1 minute

1 meter covered= (1/264) minute

5280 meters covered= (5280 / 264)

= 20 minutesIncorrectAnswer –

**2) 20 minutes**

Explanation:

Diameter of the wheel= 3m

Circumference= ∏ * diameter

= (22/7) * 3

= 66/7

Since a wheel covers a distance equal to its circumference in one revolution therefore distance covered in 28 revolutions= 28 * (66/7)

= 264m

264 meters covered= 1 minute

1 meter covered= (1/264) minute

5280 meters covered= (5280 / 264)

= 20 minutes - Question 3 of 10
##### 3. Question

1 pointsCategory: Quantitative Aptitude**A man and a boy can complete a work together in 24 days. If for the last six days boy alone does the work then it is completed in 28 days. How long the man will take to complete the work alone?**CorrectAnswer –

**4) 36 days**

Explanation:

According to questions

1M + 1B complete the work in 24 days.

Last 6 days boy alone does work. They worked together for 22 days (Because the whole work complete in 28 days).

Assume total work= 24 units

(1M + 1B) per day work= 1 unit

1M + 1B do the work in 22 days= 22 units work

Rest work= 24 – 22 units= 2 units

Rest work done by Boy in 6 days.

Hence, per day work of boy= 2/6

= 1/3 unit per day

Man per day work= 1- 1/3

= 2/3

Man alone can do work= Total Work/ Efficiency of man

= (24/2) * 3

= 12 * 3

= 36 daysIncorrectAnswer –

**4) 36 days**

Explanation:

According to questions

1M + 1B complete the work in 24 days.

Last 6 days boy alone does work. They worked together for 22 days (Because the whole work complete in 28 days).

Assume total work= 24 units

(1M + 1B) per day work= 1 unit

1M + 1B do the work in 22 days= 22 units work

Rest work= 24 – 22 units= 2 units

Rest work done by Boy in 6 days.

Hence, per day work of boy= 2/6

= 1/3 unit per day

Man per day work= 1- 1/3

= 2/3

Man alone can do work= Total Work/ Efficiency of man

= (24/2) * 3

= 12 * 3

= 36 days - Question 4 of 10
##### 4. Question

1 pointsCategory: Quantitative Aptitude**A man covers 9/20 by bus and the remaining 10 Km on foot. Find his total journey (in Km)?**CorrectAnswer –

**5) 18.18**

Explanation:

Man covers 9/20 of the journey by bus

= Remaining Journey= 1 – (9/20)

= 11/20

According to question,

11/20 of the journey= (20/11) * 10

= 18.18 KmIncorrectAnswer –

**5) 18.18**

Explanation:

Man covers 9/20 of the journey by bus

= Remaining Journey= 1 – (9/20)

= 11/20

According to question,

11/20 of the journey= (20/11) * 10

= 18.18 Km - Question 5 of 10
##### 5. Question

1 pointsCategory: Quantitative Aptitude**A bag contains 75 balls out of which at least 15 balls are red. If three balls are picked at random from the bag, what is the probability that one of the balls is not red?**

I. Only 35 balls in the bag are blue.

II. When a ball is picked at random from the bag, the probability of the ball being white is 1/5.

III. When two balls are picked at random from the bag, the probability of both the ball being green is 12/925.CorrectAnswer –

**5) All three statements together are not sufficient to answer the question.**

Explanation:From I

We know about 15 + 35= 50 balls

But we do not know the color of remaining 25 ballsFrom II

When a ball is picked at random from the bag, the probability of the ball being white= 1/5

=15/75

So, the number of white balls= 15

Using I and II

We know about 15 + 35 + 15= 65 balls

But still we do not know the color of remaining 10 ballsFrom III

When two balls are picked at random from the bag, the probability of both the ball being green = 12/925

^{n}C_{2}/^{75}C_{2}= 12/925

Where n is number of green balls

N(n-1) / (75 * 74) = 12/925

N=9

Using I and III or II and III or all I, II and III together we cannot determine the exact number of red balls in the bag.IncorrectAnswer –

**5) All three statements together are not sufficient to answer the question.**

Explanation:From I

We know about 15 + 35= 50 balls

But we do not know the color of remaining 25 ballsFrom II

When a ball is picked at random from the bag, the probability of the ball being white= 1/5

=15/75

So, the number of white balls= 15

Using I and II

We know about 15 + 35 + 15= 65 balls

But still we do not know the color of remaining 10 ballsFrom III

When two balls are picked at random from the bag, the probability of both the ball being green = 12/925

^{n}C_{2}/^{75}C_{2}= 12/925

Where n is number of green balls

N(n-1) / (75 * 74) = 12/925

N=9

Using I and III or II and III or all I, II and III together we cannot determine the exact number of red balls in the bag. - Question 6 of 10
##### 6. Question

1 pointsCategory: Quantitative Aptitude**Study the following table carefully to answer the following questions**

Percentage of the students studying various disciplines in the university

**How many male students are studying Sociology and commerce together?**CorrectAnswer –

**3) 872**

Explanation

Male students in Sociology and Commerce

=[ 4800 x 24/100 x 3/8 ] + [ 4800 x 22/100 x 5/12 ]

=432 + 440

=872IncorrectAnswer –

**3) 872**

Explanation

Male students in Sociology and Commerce

=[ 4800 x 24/100 x 3/8 ] + [ 4800 x 22/100 x 5/12 ]

=432 + 440

=872 - Question 7 of 10
##### 7. Question

1 pointsCategory: Quantitative Aptitude**Study the following table carefully to answer the following questions**

Percentage of the students studying various disciplines in the university

**What is the ratio between the number of female students Management and Computer respectively?**CorrectAnswer –

**4) 16:27**

Explanation

Req.Ratio = 4800 x 12/100 x 3/9 : 4800 x 18/100 x 3/8

=4 : 27/4

=16: 27IncorrectAnswer –

**4) 16:27**

Explanation

Req.Ratio = 4800 x 12/100 x 3/9 : 4800 x 18/100 x 3/8

=4 : 27/4

=16: 27 - Question 8 of 10
##### 8. Question

1 pointsCategory: Quantitative Aptitude**Study the following table carefully to answer the following questions**

Percentage of the students studying various disciplines in the university

**What is the total number of female students studying Commerce, English and Engineering together ?**CorrectAnswer –

**5) 1000**

Explanation

Female students in Commerce , English and Engineering

= 4800 x 22/100 x 7/12 + 4800 x 7/100 x 4/7 + 4800 x 9/100 x 4/9

= 616 + 192 + 192

=1000IncorrectAnswer –

**5) 1000**

Explanation

Female students in Commerce , English and Engineering

= 4800 x 22/100 x 7/12 + 4800 x 7/100 x 4/7 + 4800 x 9/100 x 4/9

= 616 + 192 + 192

=1000 - Question 9 of 10
##### 9. Question

1 pointsCategory: Quantitative Aptitude**Study the following table carefully to answer the following questions**

Percentage of the students studying various disciplines in the university

**What is the difference between the male students studying Sociology and Female students studying Anthropology ?**CorrectAnswer –

**2) 176**

Explanation

Req.difference = [4800 x 24/100 x 3/8] – [4800 x 8/100 x 2/3 ]

=432 – 256

=176IncorrectAnswer –

**2) 176**

Explanation

Req.difference = [4800 x 24/100 x 3/8] – [4800 x 8/100 x 2/3 ]

=432 – 256

=176 - Question 10 of 10
##### 10. Question

1 pointsCategory: Quantitative Aptitude**√3844 x √2116 -51**^{2}– √121 = √(?) + 15^{2}– √25CorrectAnswer –

**3) 400**

Explanation

= √3844 x √2116 -512 – √121 = √(?) + 152 – √25

= 62 x 46 – 2601 – 11 -225 +5

= 20IncorrectAnswer –

**3) 400**

Explanation

= √3844 x √2116 -512 – √121 = √(?) + 152 – √25

= 62 x 46 – 2601 – 11 -225 +5

= 20

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