# IBPS RRB 2017 Prelim : Quants Test Day 25

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- Question 1 of 10
##### 1. Question

1 pointsCategory: Quantitative AptitudeWhat is the ratio of students enrolled in Dancing from city A and E to Craft from city B and C taken together?

CorrectExplanation

Students enrolled in Dancing from city A and E = (24500 + 17500) = 42000

Students enrolled in Craft from city B and C = (22500 + 26500) = 49000

Required ratio = 42000/49000 = 6:7IncorrectExplanation

Students enrolled in Dancing from city A and E = (24500 + 17500) = 42000

Students enrolled in Craft from city B and C = (22500 + 26500) = 49000

Required ratio = 42000/49000 = 6:7 - Question 2 of 10
##### 2. Question

1 pointsCategory: Quantitative AptitudeWhat is average enrollment in craft taken in all cities together?

CorrectExplanation

Total enrollment in craft = (20000 + 22500 + 26500 + 20000 + 24000 + 26500) = 139500

Required average = 139500/6 = 23250IncorrectExplanation

Total enrollment in craft = (20000 + 22500 + 26500 + 20000 + 24000 + 26500) = 139500

Required average = 139500/6 = 23250 - Question 3 of 10
##### 3. Question

1 pointsCategory: Quantitative AptitudeIf 45%, 40% and 42% of students enrolled from city C in Dancing, Drawing and Craft are female then what is difference of male to female students enrolled taken all three activities together?

CorrectExplanation

Difference in dancing = 18000 x (55 – 45)/100 = 1800

Difference in drawing = 21500 x (60 – 40)/100 = 4300

Difference in craft = 26500 x (58 – 42)/100 = 4240

Required difference = (1800 + 4300 + 4240) = 10340IncorrectExplanation

Difference in dancing = 18000 x (55 – 45)/100 = 1800

Difference in drawing = 21500 x (60 – 40)/100 = 4300

Difference in craft = 26500 x (58 – 42)/100 = 4240

Required difference = (1800 + 4300 + 4240) = 10340 - Question 4 of 10
##### 4. Question

1 pointsCategory: Quantitative AptitudeIf 18% and 25% students in city D and 20% and 25% of students in city A respectively from dancing

and Drawing are professional then what is the ratio of professional students enrolled in craft from A to D?CorrectExplanation

From city A:

Dancing professional = 24500 x 20/100 = 4900

Drawing professional = 24000 x 25/100 = 6000 Total = (4900 + 6000) = 10900

Total professional = 15300 Craft professional = (15300 – 10900) = 4400

From city D:

Dancing professional = 20000 x 18/100 = 3600

Drawing professional = 18000 x 25/100 = 4500

Total = (3600 + 4500) = 8100

Total professional = 15300

Craft professional = (15300 – 8100) = 7200

Required ratio = 4400/7200 = 11:18IncorrectExplanation

From city A:

Dancing professional = 24500 x 20/100 = 4900

Drawing professional = 24000 x 25/100 = 6000 Total = (4900 + 6000) = 10900

Total professional = 15300 Craft professional = (15300 – 10900) = 4400

From city D:

Dancing professional = 20000 x 18/100 = 3600

Drawing professional = 18000 x 25/100 = 4500

Total = (3600 + 4500) = 8100

Total professional = 15300

Craft professional = (15300 – 8100) = 7200

Required ratio = 4400/7200 = 11:18 - Question 5 of 10
##### 5. Question

1 pointsCategory: Quantitative AptitudeTotal enrollment from city B and F is approximately what percent more than that of C and E taken all activities together?

CorrectExplanation

Total enrollment from B and F = (73000 + 71000) = 144000

Total enrollment from C and E = (66000 + 64000) = 130000

Required percent = (144000 – 130000)/130000 x 100 ≈ 11%IncorrectExplanation

Total enrollment from B and F = (73000 + 71000) = 144000

Total enrollment from C and E = (66000 + 64000) = 130000

Required percent = (144000 – 130000)/130000 x 100 ≈ 11% - Question 6 of 10
##### 6. Question

1 pointsCategory: Quantitative AptitudeIn a simultaneous thrown of two dice. What is the probability of getting a total of either 9 or 10?

CorrectIncorrect - Question 7 of 10
##### 7. Question

1 pointsCategory: Quantitative AptitudeA hollow cylindrical tube is open at both ends is made of iron 4cm thick. If the external diameter be 52cm and the length of the tube be 120cm, find the number of cubic cm of iron in it? approx

CorrectExplanation

H = 120 external diameter – 52

External radius = 26

Internal radius = 26-4 =22

Volume of iron = external volume – internal volume

22/7 * 26 * 26 * 120 – 22/7 * 22 * 22 * 120 = 72411IncorrectExplanation

H = 120 external diameter – 52

External radius = 26

Internal radius = 26-4 =22

Volume of iron = external volume – internal volume

22/7 * 26 * 26 * 120 – 22/7 * 22 * 22 * 120 = 72411 - Question 8 of 10
##### 8. Question

1 pointsCategory: Quantitative AptitudeA man cover a distance in t hrs, if he met with an accident after 20km and he then run at his 3/5th of his normal speed, so he reaches his destination 40minutes late. If he met with an accident at 30km then he reaches only 30min late. Find his original speed?

CorrectExplanation

After moving 10km more, man saves 10minutes. For saving of 40minutes he has to cover 40km.

Now speed: after accident before accident

. 3 5

Time 5 3

. (+2)

2=40minutes

1=20min

(Normal time) 3= 60min

So, he covers 40km in 60min with normal speed = 40kmphIncorrectExplanation

After moving 10km more, man saves 10minutes. For saving of 40minutes he has to cover 40km.

Now speed: after accident before accident

. 3 5

Time 5 3

. (+2)

2=40minutes

1=20min

(Normal time) 3= 60min

So, he covers 40km in 60min with normal speed = 40kmph - Question 9 of 10
##### 9. Question

1 pointsCategory: Quantitative AptitudeX, Y and Z started a business with their investments in the ratio 1:2:4. After 6 months X invested the half amount more as before and Y invested twice the amount as before while Z withdraw 1/4th of their investments. Find the ratio of their profits at the end of the year.

CorrectExplanation

Let us assume their initial investments were x, 2x and 4x respectively.

Therefore, ratio of their investments during the whole year

= [(x * 6) + (3x/2 * 6)]: [(2x * 6) + (4x * 6)]: [(4x * 6) + (3x * 6)]

= 15x: 36x: 42x

= 5 :12 :14IncorrectExplanation

Let us assume their initial investments were x, 2x and 4x respectively.

Therefore, ratio of their investments during the whole year

= [(x * 6) + (3x/2 * 6)]: [(2x * 6) + (4x * 6)]: [(4x * 6) + (3x * 6)]

= 15x: 36x: 42x

= 5 :12 :14 - Question 10 of 10
##### 10. Question

1 pointsCategory: Quantitative AptitudeThe difference between a two-digit number and the number obtained by interchanging two digits of the number is 9. The sum of the two digits of the number is 15. What is the product of two digits of two-digit number?

CorrectExplanation

Let the digit of unit place be x.

So, the digit of tens place will be (15 ⎯x)

[10 (15 ⎯x) + x]⎯[10x + (15 ⎯x)] = 9

150 ⎯10x + x ⎯10x ⎯15 + x = 9

135 ⎯18 x = 9

18x = 126

x = 7

Thus, the digits of the number are 7 and 8.

So, the multiple of digits = 56IncorrectExplanation

Let the digit of unit place be x.

So, the digit of tens place will be (15 ⎯x)

[10 (15 ⎯x) + x]⎯[10x + (15 ⎯x)] = 9

150 ⎯10x + x ⎯10x ⎯15 + x = 9

135 ⎯18 x = 9

18x = 126

x = 7

Thus, the digits of the number are 7 and 8.

So, the multiple of digits = 56

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