# IBPS RRB Clerk 2019 Prelims: Quant Test Day 7

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- Question 1 of 10
##### 1. Question

1 pointsCategory: Quantitative Aptitude**The difference between downstream speed and upstream speed of the boat is 8 km/hr and boat travels 48 km from P to Q (upstream) in 6 hours. Then find the speed of the boat in still water?**Correct**Answer: 3) 12km/hr**

Explanation:

Let the speed of boat in still water be x km/hr

And that of stream be y km/hr

ATQ,

(x+y)-(x-y) = 8

2y = 8

y = 4 km/hr

Upstream speed(x-y) = 48/6

(x-y) = 8

x-4 = 8

x = 12 km/hrIncorrect**Answer: 3) 12km/hr**

Explanation:

Let the speed of boat in still water be x km/hr

And that of stream be y km/hr

ATQ,

(x+y)-(x-y) = 8

2y = 8

y = 4 km/hr

Upstream speed(x-y) = 48/6

(x-y) = 8

x-4 = 8

x = 12 km/hr - Question 2 of 10
##### 2. Question

1 pointsCategory: Quantitative Aptitude**In a vessel, there are two types of liquids A and B in the ratio of 4: 3. 21 litres of the mixture is taken out and 8 litres of type A liquid is poured into it, the new ratio (A: B) thus formed is 3:2. Find the final quantity of mixture in the vessel?**Correct**Answer: 3) 120 litres**

Explanation:

Let the initial quantity of mixture in the vessel be x litres

ATQ,

(x*4/7 – 12+8)/(x*3/7 – 9) = 3/2

(4x – 28)/(3x – 63) = 3/2

8x-56 = 9x – 189

x = 133

Final quantity = 133-21+8

Final quantity = 120 litresIncorrect**Answer: 3) 120 litres**

Explanation:

Let the initial quantity of mixture in the vessel be x litres

ATQ,

(x*4/7 – 12+8)/(x*3/7 – 9) = 3/2

(4x – 28)/(3x – 63) = 3/2

8x-56 = 9x – 189

x = 133

Final quantity = 133-21+8

Final quantity = 120 litres - Question 3 of 10
##### 3. Question

1 pointsCategory: Quantitative Aptitude**The average age of 12 students in a group is 16.75 years. When a new student joined them, the average age is decreased by 0.75 years. Then find the age of the new student.**Correct**Answer: 2) 7 years**

Explanation:

Age of new student = 13*(16.75 – .75) – 12*16.75 = 7 yearsIncorrect**Answer: 2) 7 years**

Explanation:

Age of new student = 13*(16.75 – .75) – 12*16.75 = 7 years - Question 4 of 10
##### 4. Question

1 pointsCategory: Quantitative Aptitude**A person has purchased two adjacent plots, one is rectangular and other is square and combined them to make a single new plot. The breadth of the rectangular plot is equal to the side of the square plot and the cost of ploughing the new plot is Rs. 576 (Rs. 8/m2). Find the side of the square if the length of the rectangular plot is 14 m.**Correct**Answer: 4) 4m**

Explanation:

Let the breadth of rectangular plot be x m and length = 14 m

ATQ,

Area of new plot

x*(14+x) = 576/8

x*(14+x) = 72m2

x2+14x-72 = 0

x2+18x-4x-72 = 0

x(x+18)-4(x+18) = 0

(x-4)*(x+18) = 0

x = -18, 4 (but side of square cannot be –ve)

Therefore, side of square = 4mIncorrect**Answer: 4) 4m**

Explanation:

Let the breadth of rectangular plot be x m and length = 14 m

ATQ,

Area of new plot

x*(14+x) = 576/8

x*(14+x) = 72m2

x2+14x-72 = 0

x2+18x-4x-72 = 0

x(x+18)-4(x+18) = 0

(x-4)*(x+18) = 0

x = -18, 4 (but side of square cannot be –ve)

Therefore, side of square = 4m - Question 5 of 10
##### 5. Question

1 pointsCategory: Quantitative Aptitude**A shopkeeper marked his article 40% above the cost price and gives a discount of 10% on it. If he had marked his article 55% above the cost price and gives a discount of 15% on it then find the earlier profit is approximately what percent of the profit earned latter?**Correct**Answer: 2) 82%**

Explanation:

Let the CP be Rs. 100x

Then, MP = Rs. 140x

SP = 140x*(90/100) = 126x

Profit = 126x-100x = 26x

New MP = Rs. 155x

New SP = 155x*(85/100) = 131.75x

Profit = 131.75x-100x = 31.75x

Required % = (26x/31.75x)*100 = 81.88% = 82% (approx)Incorrect**Answer: 2) 82%**

Explanation:

Let the CP be Rs. 100x

Then, MP = Rs. 140x

SP = 140x*(90/100) = 126x

Profit = 126x-100x = 26x

New MP = Rs. 155x

New SP = 155x*(85/100) = 131.75x

Profit = 131.75x-100x = 31.75x

Required % = (26x/31.75x)*100 = 81.88% = 82% (approx) - Question 6 of 10
##### 6. Question

1 pointsCategory: Quantitative Aptitude**Directions: (6-10)**There are total five departments in a company. There are total 160 employees in customer care department which is 20% of total employees in the company. 5/16 of the total employees of the company are working in the marketing department. Employees working in the digital department are 20% less than that in the marketing department. The ratio between employees working in the hardware department and software department is 11:8.**The number of employees working in the Hardware department in what percent less than the number of employees working in the digital department?**Correct**Answer: 3) 45%**

Explanation:

Required % = {(200-110)/200}*100 = (90/200)*100 = 45%Overall Explanation:

Let the total employees in the company be 100x

ATQ,

(20/100)*100x = 160

100x =800

Employees working in marketing department = (5/16)*800 = 250

Employees working in digital department = (80/100)*250 = 200

Remaining employees = 800-160-250-200 = 190

Employees working in hardware department = (11/19)*190 = 110

Employees working in software department = (8/19)*190 = 80

Incorrect**Answer: 3) 45%**

Explanation:

Required % = {(200-110)/200}*100 = (90/200)*100 = 45%Overall Explanation:

Let the total employees in the company be 100x

ATQ,

(20/100)*100x = 160

100x =800

Employees working in marketing department = (5/16)*800 = 250

Employees working in digital department = (80/100)*250 = 200

Remaining employees = 800-160-250-200 = 190

Employees working in hardware department = (11/19)*190 = 110

Employees working in software department = (8/19)*190 = 80

- Question 7 of 10
##### 7. Question

1 pointsCategory: Quantitative Aptitude**Directions: (6-10)**There are total five departments in a company. There are total 160 employees in customer care department which is 20% of total employees in the company. 5/16 of the total employees of the company are working in the marketing department. Employees working in the digital department are 20% less than that in the marketing department. The ratio between employees working in the hardware department and software department is 11:8.**Find the average number of employees working in marketing and hardware department?**Correct**Answer: 5) 180**

Explanation:

Required average = (250+110)/2 = 360/2 = 180Incorrect**Answer: 5) 180**

Explanation:

Required average = (250+110)/2 = 360/2 = 180 - Question 8 of 10
##### 8. Question

1 pointsCategory: Quantitative Aptitude**Directions: (6-10)**There are total five departments in a company. There are total 160 employees in customer care department which is 20% of total employees in the company. 5/16 of the total employees of the company are working in the marketing department. Employees working in the digital department are 20% less than that in the marketing department. The ratio between employees working in the hardware department and software department is 11:8.**The number of employees in the customer care department is how much less than the number of employees in the marketing department?**Correct**Answer: 4) 90**

Explanation:

Required difference = 250 – 160 = 90Incorrect**Answer: 4) 90**

Explanation:

Required difference = 250 – 160 = 90 - Question 9 of 10
##### 9. Question

1 pointsCategory: Quantitative Aptitude**Directions: (6-10)**There are total five departments in a company. There are total 160 employees in customer care department which is 20% of total employees in the company. 5/16 of the total employees of the company are working in the marketing department. Employees working in the digital department are 20% less than that in the marketing department. The ratio between employees working in the hardware department and software department is 11:8.**In the digital department, 30% of the employees are married and in the software department 85% of the employees are unmarried then find the total number of married employees in digital and software department?**Correct**Answer: 1) 72**

Explanation:

Married employees in digital department = (30/100)*200 = 60

Married employees in software department = (15/100)*80 = 12

The total number of married employees in digital and software department = 60+12 = 72Incorrect**Answer: 1) 72**

Explanation:

Married employees in digital department = (30/100)*200 = 60

Married employees in software department = (15/100)*80 = 12

The total number of married employees in digital and software department = 60+12 = 72 - Question 10 of 10
##### 10. Question

1 pointsCategory: Quantitative Aptitude**Directions: (6-10)**There are total five departments in a company. There are total 160 employees in customer care department which is 20% of total employees in the company. 5/16 of the total employees of the company are working in the marketing department. Employees working in the digital department are 20% less than that in the marketing department. The ratio between employees working in the hardware department and software department is 11:8.**The ratio between the total number of male and female employees in the marketing department is 7:3. Find the total number of male employees working in the marketing department?**Correct**Answer: 2) 75**

Explanation:

Total number of male employees working in marketing department = (3/10)*250 = 75Incorrect**Answer: 2) 75**

Explanation:

Total number of male employees working in marketing department = (3/10)*250 = 75

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