# Railway RRB 2016: Quant Test – Day 10

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- Question 1 of 10
##### 1. Question

1 pointsCategory: Quantitative AptitudeA can complete 3/5th of a piece of work in 12 days and B can complete 2/3rd of the same work in 20 days. If both A and B work together, they can do 1/6th of that work in how many days?

Correct**Explanation:**

A can do 3/5th of the work in 12 days, so whole work in 5/3 * 12 = 20 days.

B can do 2/3th of the work in 20 days, so whole work in 3/2 * 20 = 30 days.

A and B together can complete whole work in 20*30/(20+30) = 12 days.

So 1/6th work in 1/6 * 12 = 2 daysIncorrect**Explanation:**

A can do 3/5th of the work in 12 days, so whole work in 5/3 * 12 = 20 days.

B can do 2/3th of the work in 20 days, so whole work in 3/2 * 20 = 30 days.

A and B together can complete whole work in 20*30/(20+30) = 12 days.

So 1/6th work in 1/6 * 12 = 2 days - Question 2 of 10
##### 2. Question

1 pointsCategory: Quantitative AptitudeA person invested Rs 1,600 with rate of interest at 10% pa. Find the total interest earned at the end of two years if for the first year the interest was compounded half yearly and for the second year it was compounded yearly?

Correct**Explanation:**

For 1st year – time = 2, r% = 10/2 = 5%.

So Amount after 1st year = 1,600 [(1+5/100)]^{2}= Rs 1764

Amount after 2nd year = 1,764 [(1+10/100)]^{1}= Rs 1940.4

So CI = 1940.0 – 1600Incorrect**Explanation:**

For 1st year – time = 2, r% = 10/2 = 5%.

So Amount after 1st year = 1,600 [(1+5/100)]^{2}= Rs 1764

Amount after 2nd year = 1,764 [(1+10/100)]^{1}= Rs 1940.4

So CI = 1940.0 – 1600 - Question 3 of 10
##### 3. Question

1 pointsCategory: Quantitative AptitudeA and B started a business by investing Rs 1200 and Rs 1500 respectively. After 4 months, A added Rs 200 an B added Rs 100 to their investments for 8 and 6 months respectively. After a year from the start of business, they got a total profit of Rs 11,850. What is the share of A in the profit?

Correct**Explanation:**

A : B

1200*4 + 1400*8 : 1500*4 + 1600*6

12*4 + 14*8 : 15*4 + 16*6

12 + 14*2 : 15 + 8*3

40 : 39

So A got 40/79 * 11850 = 6000Incorrect**Explanation:**

A : B

1200*4 + 1400*8 : 1500*4 + 1600*6

12*4 + 14*8 : 15*4 + 16*6

12 + 14*2 : 15 + 8*3

40 : 39

So A got 40/79 * 11850 = 6000 - Question 4 of 10
##### 4. Question

1 pointsCategory: Quantitative AptitudeThe amount that A and B earns is in the ratio 6 : 5. After a year there is an equal percentage increase in their incomes and the difference in their incomes become Rs 14300. If difference in the old income of A and new income of B is Rs 6500, what is the % increase in incomes?

Correct**Explanation:**

6x and 5x

Suppose, y% increased

So (100+y)/100 * 6x – (100+y)/100 *5x = 14300

This gives (100+y)*x = 14,30,000

Now also given

6x – [(100+y)/100 * 5x] = 6500

Solve, x(20-y) = 1,30,000

Divide both equations

(100+y)/(20-y) = 11

Solve, y = 10Incorrect**Explanation:**

6x and 5x

Suppose, y% increased

So (100+y)/100 * 6x – (100+y)/100 *5x = 14300

This gives (100+y)*x = 14,30,000

Now also given

6x – [(100+y)/100 * 5x] = 6500

Solve, x(20-y) = 1,30,000

Divide both equations

(100+y)/(20-y) = 11

Solve, y = 10 - Question 5 of 10
##### 5. Question

1 pointsCategory: Quantitative AptitudeThere is a loss of 10% on an article when it is sold at 3/5 of its Marked Price. How much percent less is Cost Price than Marked Price?

Correct**Explanation:**

Let MP = x

Then SP = 3/5 * x = 3x/5

Loss is 10%, so CP = [100/(100-10)] * 3x/5 = 2x/3

So required % = [(x – 2x/3)/(x)] * 100Incorrect**Explanation:**

Let MP = x

Then SP = 3/5 * x = 3x/5

Loss is 10%, so CP = [100/(100-10)] * 3x/5 = 2x/3

So required % = [(x – 2x/3)/(x)] * 100 - Question 6 of 10
##### 6. Question

1 pointsCategory: Quantitative AptitudeThe sum of the ages of A and B is 45 yrs. Also 4 yrs ago, the B’s age was 11 less than twice the age of A that time. What is the present age of the A?

Correct**Explanation:**

A+B = 45

(B-4) = 2(A-4) – 11

Solve both equations, A = 20Incorrect**Explanation:**

A+B = 45

(B-4) = 2(A-4) – 11

Solve both equations, A = 20 - Question 7 of 10
##### 7. Question

1 pointsCategory: Quantitative AptitudeA sum became thrice when invested for 4 years at simple interest, how many times will it become in 7 years?

Correct**Explanation:**

Amount is thrice of principal, so interest is 2P

So 2P = P*r*4/100

Solve, r = 50%

So in 7 yrs interest = P*50*7/100 = 3.5P, so amount = P+ 3.5P = 4.5PIncorrect**Explanation:**

Amount is thrice of principal, so interest is 2P

So 2P = P*r*4/100

Solve, r = 50%

So in 7 yrs interest = P*50*7/100 = 3.5P, so amount = P+ 3.5P = 4.5P - Question 8 of 10
##### 8. Question

1 pointsCategory: Quantitative AptitudeDistance between point P and Q is 240 km. A train starts from point P at 6:00 AM with 60 km/hr towards Q. Another train starts from point Q towards P at 7:00 AM with 30 km/kr. At what time the trains will meet?

Correct**Explanation:**

When 2nd train starts i.e. at 7 AM (1 hr after 6 AM), distance covered by first train is 60 km (i.e. in 1 hr).

Now 2nd train also starts and distance between them is now (240-60) = 180 km

Both coming in opposite direction, so relative speed = (60+30) = 90 km/hr

So time = 7:00 AM + (180/90) = 7:00 AM +2 hrs = 9:00 AMIncorrect**Explanation:**

When 2nd train starts i.e. at 7 AM (1 hr after 6 AM), distance covered by first train is 60 km (i.e. in 1 hr).

Now 2nd train also starts and distance between them is now (240-60) = 180 km

Both coming in opposite direction, so relative speed = (60+30) = 90 km/hr

So time = 7:00 AM + (180/90) = 7:00 AM +2 hrs = 9:00 AM - Question 9 of 10
##### 9. Question

1 pointsCategory: Quantitative AptitudeHow many 4 letter words starting with vowel can be formed by the letters of word ACTIVE such that no letter repeats?

Correct**Explanation:**

There are 3 vowels, so we gave 3 choices for the first letter

There are total 6 letters in ACTIVE, and one of them has occupied first place, so 5 choices for second, 4 choices for third, and 3 choices for fourth

So 3*5*4*3 = 180Incorrect**Explanation:**

There are 3 vowels, so we gave 3 choices for the first letter

There are total 6 letters in ACTIVE, and one of them has occupied first place, so 5 choices for second, 4 choices for third, and 3 choices for fourth

So 3*5*4*3 = 180 - Question 10 of 10
##### 10. Question

1 pointsCategory: Quantitative AptitudeWhich is the least fraction out of 2/5, 4/7, 3/8 and 1/4?

Correct**Explanation:**

Do by finding their decimal values

OR

Compare each

First – 2/5 and 4/7

2*7 = 14 and 4*5 = 20

So 2/5 is small than 4/7

Next – 2/5 and 3/8

2*8 = 16 and 3*5 = 15

So 3/8 is small than 2/5

Next – 3/8 and 1/4

3*4 = 14 and 1*8 = 8

So 1/4 is smallestIncorrect**Explanation:**

Do by finding their decimal values

OR

Compare each

First – 2/5 and 4/7

2*7 = 14 and 4*5 = 20

So 2/5 is small than 4/7

Next – 2/5 and 3/8

2*8 = 16 and 3*5 = 15

So 3/8 is small than 2/5

Next – 3/8 and 1/4

3*4 = 14 and 1*8 = 8

So 1/4 is smallest

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