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Question 1 of 10

1. Question

1 points

Category: Quantitative Aptitude

The place value of 5 in 24568 is

Correct

Explanation:
Place value of 2 in 24568 is 20000, of 4 is 4000 and so on.

Incorrect

Explanation:
Place value of 2 in 24568 is 20000, of 4 is 4000 and so on.

Question 2 of 10

2. Question

1 points

Category: Quantitative Aptitude

In a mixture of 100 litres, the ratio of milk and water is 4 : 1. If this ratio is to be 1 : 4, the quantity of water to be added in mixture is

Correct

Explanation:
Milk = 4/5 * 100 = 80, so water is 20 l
Now let x l of water to be added, so
80/(20+x) = 1/4
Solve, x = 300 l

Incorrect

Explanation:
Milk = 4/5 * 100 = 80, so water is 20 l
Now let x l of water to be added, so
80/(20+x) = 1/4
Solve, x = 300 l

Question 3 of 10

3. Question

1 points

Category: Quantitative Aptitude

If 400 coins consists of 25 paise, 50 paise and rupee coins whose values are in the ratio of 1 : 3 : 6. The number of 50 paise coins is

Correct

Explanation:
Let coins be a, b, c resp.
Then a+b+c = 400
Now values are x, 3x and 6x
Then, x = (25/100)*a, so a = 4x
3x = (50/100)*b, so b = 6x
And 6x = 1*c, so c = 6x
So now a+b+c = 400, so 4x + 6x + 6x = 400
Solve, x = 25
50 paise coins are b which equals 6x = 6*50 = 150

Incorrect

Explanation:
Let coins be a, b, c resp.
Then a+b+c = 400
Now values are x, 3x and 6x
Then, x = (25/100)*a, so a = 4x
3x = (50/100)*b, so b = 6x
And 6x = 1*c, so c = 6x
So now a+b+c = 400, so 4x + 6x + 6x = 400
Solve, x = 25
50 paise coins are b which equals 6x = 6*50 = 150

Question 4 of 10

4. Question

1 points

Category: Quantitative Aptitude

How many three digit numbers are there each of which is divisible by 5?

Correct

Explanation:
For a number to be divisible by 5, the last digit should be 0 or 5, so two choices for last digit, 9 choices (1-9) for first digit and 10 choices (0-9) for second digit.
So total = 9*10*2 = 180

Incorrect

Explanation:
For a number to be divisible by 5, the last digit should be 0 or 5, so two choices for last digit, 9 choices (1-9) for first digit and 10 choices (0-9) for second digit.
So total = 9*10*2 = 180

Question 5 of 10

5. Question

1 points

Category: Quantitative Aptitude

A and B can complete a piece of work in 12 and 15 days respectively. They started the work, and after 3 days A left the work. In how many days did B completed the remaining work?

Correct

Explanation:
A and B = (1/12 + 1/15) = 3/20
They worked for 3 days, so they did 3/20 * 3 = 9/20 of the work
Now B has to complete the remaining work = 1 – 9/20 = 11/20
So (1/15)*x = 11/20
Solve, x = 8 1/4 days

Incorrect

Explanation:
A and B = (1/12 + 1/15) = 3/20
They worked for 3 days, so they did 3/20 * 3 = 9/20 of the work
Now B has to complete the remaining work = 1 – 9/20 = 11/20
So (1/15)*x = 11/20
Solve, x = 8 1/4 days

Question 6 of 10

6. Question

1 points

Category: Quantitative Aptitude

Four years ago, the ratio of ages of Amit and Bhuvan was 7 : 11. 5 years hence the respective ratio will be 5 : 7. Find the sum of their present ages.

Correct

Explanation:
7x and 11x
4+5 years now
So (7x+9)/(11x+9) = 5/7
Solve, x = 3
So Amit’s present age = 7x + 4 = 25 and Bhuvan’s = 11x+4 = 37
So sum = 25+37

Incorrect

Explanation:
7x and 11x
4+5 years now
So (7x+9)/(11x+9) = 5/7
Solve, x = 3
So Amit’s present age = 7x + 4 = 25 and Bhuvan’s = 11x+4 = 37
So sum = 25+37

Question 7 of 10

7. Question

1 points

Category: Quantitative Aptitude

Find the least number which when divided by 9, 12, 20 and 24 leaves the same remainder 4 in each case.

Correct

Explanation:
It will be the LCM of these numbers + 4
So 360 + 4

Incorrect

Explanation:
It will be the LCM of these numbers + 4
So 360 + 4

Question 8 of 10

8. Question

1 points

Category: Quantitative Aptitude

On a certain sum of money, after 2 years the simple interest and compound interest obtained are Rs 720 and Rs 792 respectively. What is the sum of money invested?

Correct

Explanation:
Diff = 792-720 = 72
r = 2*Diff*100/SI
So r = 2*72*100/720 = 20%
Now 72 = Pr^{2}/100^{2}
Solve, P = 1800

Incorrect

Explanation:
Diff = 792-720 = 72
r = 2*Diff*100/SI
So r = 2*72*100/720 = 20%
Now 72 = Pr^{2}/100^{2}
Solve, P = 1800

Question 9 of 10

9. Question

1 points

Category: Quantitative Aptitude

By selling 70 articles, a tradesman makes a gain equal to the selling price of 10 articles. Find his gain%.

Correct

Explanation:
S.P of 70 articles – C.P of 70 articles = S.P of 10 articles
S.P of 60 articles = C.P of 70 articles
gain% = [(70 – 60)/60] * 100 = 100/6%

Incorrect

Explanation:
S.P of 70 articles – C.P of 70 articles = S.P of 10 articles
S.P of 60 articles = C.P of 70 articles
gain% = [(70 – 60)/60] * 100 = 100/6%

Question 10 of 10

10. Question

1 points

Category: Quantitative Aptitude

Two pipes A and B can alone fill a tank in 10 minutes and 15 minutes respectively. But due to a leak at the bottom of tank, it took 4 more minutes to fill the tank. In how many minutes, the leak can alone empty the full tank?

Correct

Explanation:
A and B can fill tank in (10*15)/(10+15) = so 6 minutes
But it took 4 more minutes, this means the tank got full in 6+4 = 10 minutes
So (1/10 + 1/15 – 1/x) = 1/10
Solve, x = 15

Incorrect

Explanation:
A and B can fill tank in (10*15)/(10+15) = so 6 minutes
But it took 4 more minutes, this means the tank got full in 6+4 = 10 minutes
So (1/10 + 1/15 – 1/x) = 1/10
Solve, x = 15