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Question 1 of 10

1. Question

1 points

Category: Quantitative Aptitude

A can complete 1/3rd of a piece of work in 10 days and B can complete 1/5th of the same work in 5 days. If both A and B work together, they can do 1/15th of that work in how many days?

Correct

Explanation:
A can do 1/3rd of the work in 10 days, so whole work in 3/1 * 10 = 30 days.
B can do 1/5th of the work in 5 days, so whole work in 5/1 * 5 = 25 days.
A and B together can complete whole work in 30*25/(30+25) = 150/11 days.
So 1/15th work in 1/15 * (150/11) = 10/11 days

Incorrect

Explanation:
A can do 1/3rd of the work in 10 days, so whole work in 3/1 * 10 = 30 days.
B can do 1/5th of the work in 5 days, so whole work in 5/1 * 5 = 25 days.
A and B together can complete whole work in 30*25/(30+25) = 150/11 days.
So 1/15th work in 1/15 * (150/11) = 10/11 days

Question 2 of 10

2. Question

1 points

Category: Quantitative Aptitude

The amount that A and B earns is in the ratio 4 : 3. After a year, A’s salary got increased by 20% and B’s salary by 25%. If now the total of their salaries become Rs 1,02,600, What was the initial salary of A?

Correct

Explanation:
4x and 3x
After year, As salary = (120/100)*4x = 480x/100, Bs salary = (125/100)*3x = 375x/100
So addition of their salaries = (480x/100) +(375x/100) = 855x/100
So 855x/100 = 1,02,600
Solve, x = 12,000
So As initial salary = 4x = 4*12000

Incorrect

Explanation:
4x and 3x
After year, As salary = (120/100)*4x = 480x/100, Bs salary = (125/100)*3x = 375x/100
So addition of their salaries = (480x/100) +(375x/100) = 855x/100
So 855x/100 = 1,02,600
Solve, x = 12,000
So As initial salary = 4x = 4*12000

Question 3 of 10

3. Question

1 points

Category: Quantitative Aptitude

The sum of the ages of A and B is 50 yrs. Also 4 yrs ago, the B’s age was 6 less than twice the age of A that time. What is the present age of the B?

Correct

Explanation:
A+B = 50
(B-4) = 2(A-4) – 6
Solve both equations, B = 30

Incorrect

Explanation:
A+B = 50
(B-4) = 2(A-4) – 6
Solve both equations, B = 30

Question 4 of 10

4. Question

1 points

Category: Quantitative Aptitude

How many 4 letter words starting with vowel can be formed by the letters of word QUANTS such that no letter repeats?

Correct

Explanation:
There are 2 vowels, so we gave 2 choices for the first letter
There are total 6 letters in QUANTS, and one of them has occupied first place, so 5 choices for second, 4 choices for third, and 3 choices for fourth
So 2*5*4*3 = 120

Incorrect

Explanation:
There are 2 vowels, so we gave 2 choices for the first letter
There are total 6 letters in QUANTS, and one of them has occupied first place, so 5 choices for second, 4 choices for third, and 3 choices for fourth
So 2*5*4*3 = 120

Question 5 of 10

5. Question

1 points

Category: Quantitative Aptitude

A and B invested Rs 1400 and Rs 1550. After 4 months, A added Rs 200 and B withdrawn Rs 100. If after a year a total profit of Rs 45,250 is made, what is the share of A in the profit?

The cost of material is divides in its raw materials, labour cost and transportation in the ratio 4 : 9 : 5. If the labour cost on the making of material was Rs 8100, what is the cost of material?

Correct

Explanation:
4 : 9 : 5
So 9/(4+9+5) * x = 8100
So, x = 16200

Incorrect

Explanation:
4 : 9 : 5
So 9/(4+9+5) * x = 8100
So, x = 16200

Question 7 of 10

7. Question

1 points

Category: Quantitative Aptitude

The place value of 2 in 27814 is

Correct

Explanation:
Place value of 2 in 27814 is 20000, of 7 is 7000 and so on.

Incorrect

Explanation:
Place value of 2 in 27814 is 20000, of 7 is 7000 and so on.

Question 8 of 10

8. Question

1 points

Category: Quantitative Aptitude

In a mixture of 120 litres, the ratio of milk and water is 5 : 3. If this ratio is to be 3 : 1, the quantity of water to be removed from the mixture is

Correct

Explanation:
Milk = 5/8 * 120 = 75, so water is 45 l
Now let x l of water to be removed, so
75/(45-x) = 3/1
Solve, x = 20 l

Incorrect

Explanation:
Milk = 5/8 * 120 = 75, so water is 45 l
Now let x l of water to be removed, so
75/(45-x) = 3/1
Solve, x = 20 l

Question 9 of 10

9. Question

1 points

Category: Quantitative Aptitude

If y : x = 4 : 9, then the value of (x-y)/(x+y) is

Correct

Explanation:
y/x = 4/9
(x-y)/(x+y)
Take x common from num. and den. both and cancel
So (x-y)/(x+y) = (1 – y/x)/(1 + y/x)
= (1 – 4/9)/ (1 + 4/9) = 5/13

Incorrect

Explanation:
y/x = 4/9
(x-y)/(x+y)
Take x common from num. and den. both and cancel
So (x-y)/(x+y) = (1 – y/x)/(1 + y/x)
= (1 – 4/9)/ (1 + 4/9) = 5/13

Question 10 of 10

10. Question

1 points

Category: Quantitative Aptitude

The orthocenter of a right angled triangle lies

Correct

Explanation:
The orthocenter is the point where the three altitudes of a triangle intersect.

Incorrect

Explanation:
The orthocenter is the point where the three altitudes of a triangle intersect.