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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeDirections (1–4) Study the given line graph carefully and answer the questions that follow.
The graph given below shows the number of employees in two departments of company ABC from year 2010 to 2015.
In which year is the percentage increase in the number of employees over the previous year the highest for IT department?
Correct
Explanation:
In 2011, % increase is (26001800)/1800 * 100 = 44.4%
In 2012, 2013 the number is decreasing
In 2014, % increase is (20501950)/1950 * 100 = 5.12%Incorrect
Explanation:
In 2011, % increase is (26001800)/1800 * 100 = 44.4%
In 2012, 2013 the number is decreasing
In 2014, % increase is (20501950)/1950 * 100 = 5.12% 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeDirections (1–4) Study the given line graph carefully and answer the questions that follow.
The graph given below shows the number of employees in two departments of company ABC from year 2010 to 2015.
Number of employees in HR department is approximately what percentage of the total number of employees in both departments together in the year 2014?
Correct
Explanation:
In 2014, in HR = 1200
In HR + IT = 1200 + 2050 = 3250
So required % = (1200/3250)*100 = 36.9Incorrect
Explanation:
In 2014, in HR = 1200
In HR + IT = 1200 + 2050 = 3250
So required % = (1200/3250)*100 = 36.9 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeDirections (1–4) Study the given line graph carefully and answer the questions that follow.
The graph given below shows the number of employees in two departments of company ABC from year 2010 to 2015.
What is the average number of employees in IT Department over all years?
Correct
Explanation:
1800+2600+2400+1950+2050+2200 / 6 = 800Incorrect
Explanation:
1800+2600+2400+1950+2050+2200 / 6 = 800 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeDirections (1–4) Study the given line graph carefully and answer the questions that follow.
The graph given below shows the number of employees in two departments of company ABC from year 2010 to 2015.
Number of employees in HR department in 2012 is what percent less than that of IT department in the same year?
Correct
Explanation:
(24001900)/2400] * 100 = 20.8%Incorrect
Explanation:
(24001900)/2400] * 100 = 20.8% 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeHow many 4 digit numbers can be made from the digits 3, 5, 7, 9, 0, and 6 without repetition?
Correct
Explanation:
0 cannot be on first place for it to be a 4 digit number,
So for 1st digit 5 choices, for second also 5 (because 0 can be placed here), then 4 for third place, 3 for fourth place
Total numbers = 5*5*4*3Incorrect
Explanation:
0 cannot be on first place for it to be a 4 digit number,
So for 1st digit 5 choices, for second also 5 (because 0 can be placed here), then 4 for third place, 3 for fourth place
Total numbers = 5*5*4*3 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeA and B alone can do a piece of work in 20 and 25 days respectively. In how many days the work will be completed if they both work on alternate days starting with A?
Correct
Explanation:
A = 20 days, B = 25 days
Total work = LCM(20,25) = 100
So efficiency of A = 100/20 = 5, efficiency of B= 100/25 = 4
2 days work of both = 5+4 = 9
2*11(22) days work of both = 9*11 = 99
So remaining work = 10099 = 1
Now A’s turn on 23rd day, he will do remaining work(1) in 1/5 day
So total 22 1/5 daysIncorrect
Explanation:
A = 20 days, B = 25 days
Total work = LCM(20,25) = 100
So efficiency of A = 100/20 = 5, efficiency of B= 100/25 = 4
2 days work of both = 5+4 = 9
2*11(22) days work of both = 9*11 = 99
So remaining work = 10099 = 1
Now A’s turn on 23rd day, he will do remaining work(1) in 1/5 day
So total 22 1/5 days 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeThe ratio of monthly salaries of son to father is 2 : 5, and that of mother to son is 3 : 2. If son’s annual salary is Rs 3,00,000, then what is the monthly salary of mother?
Correct
Explanation:
S : F = 2 : 5, M : S = 3 : 2
Or F/S = 5/2, and S/M = 2/3, So F : S : M = 5*2 : 2*2 : 2*3 = 10 : 4 : 6 = 5 : 2 : 3
Annual salry of son = 3,00,000 so monthly is 3,00,000/12 = 25,000
So 2/(5+2+3) * x = 25,000
Solve, x = 1,25,000
So mother’s monthly salary = 3/(5+2+3) * 1,25,000 = 37,500Incorrect
Explanation:
S : F = 2 : 5, M : S = 3 : 2
Or F/S = 5/2, and S/M = 2/3, So F : S : M = 5*2 : 2*2 : 2*3 = 10 : 4 : 6 = 5 : 2 : 3
Annual salry of son = 3,00,000 so monthly is 3,00,000/12 = 25,000
So 2/(5+2+3) * x = 25,000
Solve, x = 1,25,000
So mother’s monthly salary = 3/(5+2+3) * 1,25,000 = 37,500 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeThe ratio of the age of A 4 years hence and B’s present age is 8 : 9. After 12 years A’s age will be 12 less than twice B’s present age. Find the ratio of A’s present age to B’s age 4 years ago.
Correct
Explanation:
(A+4)/B = 8/9 so 9A – 8B = 36
Also (A+12) = 2B – 12, so A – 2B = 24
Solve, both equations, A = 12, B= 18
So required ratio is 12/(184) = 12/14Incorrect
Explanation:
(A+4)/B = 8/9 so 9A – 8B = 36
Also (A+12) = 2B – 12, so A – 2B = 24
Solve, both equations, A = 12, B= 18
So required ratio is 12/(184) = 12/14 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeA started from point P at 11 AM towards Point Q at 40 km/hr. also B started from point Q at 1 PM towards Point P at 50 km/hr. If points P and Q are 110 km apart, at what time do they meet?
Correct
Explanation:
A starts at 11 Am, after 2 hrs i.e. at 1 PM, he has covered distance = 2*40 = 80 km
Now B also started, distance between them is now 11080 = 30 km
So time they meet = 1 PM + (30/(40+50)) = 1 PM + (1/3)*60 = 1:20 PMIncorrect
Explanation:
A starts at 11 Am, after 2 hrs i.e. at 1 PM, he has covered distance = 2*40 = 80 km
Now B also started, distance between them is now 11080 = 30 km
So time they meet = 1 PM + (30/(40+50)) = 1 PM + (1/3)*60 = 1:20 PM 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeThe speed of boat A is 3 km/hr less than the speed of boat B. The time taken by boat A to travel a distance of 18 km downstream is 1 hour more than time taken by B to travel the same distance downstream. If the speed of the current is half of the speed of boat A, what is the speed of boat A?
Correct
Explanation:
Speed of A = x, then of B = x+3
Speed of current = x/2
So downstream speed from boat A = x + x/2 = 3x/2
downstream speed from boat B = x+3 + x/2 = 3x/2 + 3
so 18/(3x/2) = 18/(3x/2 + 3) + 1
36/3x = 36/(3x+6) + 1
12/x = 12/(x+2) + 1
12(x+2) = 12x + x(x+2)
x^{2} + 2x – 24 = 0
solve, x = 4Incorrect
Explanation:
Speed of A = x, then of B = x+3
Speed of current = x/2
So downstream speed from boat A = x + x/2 = 3x/2
downstream speed from boat B = x+3 + x/2 = 3x/2 + 3
so 18/(3x/2) = 18/(3x/2 + 3) + 1
36/3x = 36/(3x+6) + 1
12/x = 12/(x+2) + 1
12(x+2) = 12x + x(x+2)
x^{2} + 2x – 24 = 0
solve, x = 4
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