# SBI Clerk 2019 Prelims: Quant Test Day 10

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- Question 1 of 10
##### 1. Question

1 pointsCategory: Quantitative Aptitude**5, 7, 11, 19, 35, (?), 131**CorrectIncorrect - Question 2 of 10
##### 2. Question

1 pointsCategory: Quantitative Aptitude**15*0.8-22.2+8.8=? – 3.4**Correct**Answer: 1) 2**

Explanation:

15*0.8-22.2+8.8=? – 3.4

12 +3.4+8.8-22.2 =?

24.2 -22.2 =?

2 = ?Incorrect**Answer: 1) 2**

Explanation:

15*0.8-22.2+8.8=? – 3.4

12 +3.4+8.8-22.2 =?

24.2 -22.2 =?

2 = ? - Question 3 of 10
##### 3. Question

1 pointsCategory: Quantitative Aptitude**x**^{2}-21x+98 =0

**y**^{2}-24y+119=0Correct**Answer: 3) x = y or relationship can’t be determined.**

**Explanation:**

x^{2}-21x+98 =0

x^{2}-7x-14x+98 =0

x^{2}-7x-14x+98 =0

x(x-7)-14(x-7)=0

x=7,14y

^{2}-24y+119=0

y^{2}-7y-17x+119=0

y(y-7)-17(y-7)=0

y=7,17Incorrect**Answer: 3) x = y or relationship can’t be determined.**

**Explanation:**

x^{2}-21x+98 =0

x^{2}-7x-14x+98 =0

x^{2}-7x-14x+98 =0

x(x-7)-14(x-7)=0

x=7,14y

^{2}-24y+119=0

y^{2}-7y-17x+119=0

y(y-7)-17(y-7)=0

y=7,17 - Question 4 of 10
##### 4. Question

1 pointsCategory: Quantitative Aptitude**Area of a rectangle is 1500 sq m and respective ratio of its length and breadth is 5:3. Area of a circle is 114 sq m less than that of rectangle then**

Quantity 1. Perimeter of rectangle

Quantity 2. Circumference of circleCorrect**Answer: 1) Quantity I > Quantity II**

**Explanation:**

Let the length and breadth of rectangle be 5x and 4x respectively.

5x*3x = 1500

X = 10, length = 5*10 = 50 and breadth = 3*10 = 30

Perimeter of rectangle = 2(50+30) = 160 m

Area of circle = 1500-114 = 1386sq m

22/7 r^{2}= 1386

r= 21

Circumference of circle = 2 * 22/7* 21 = 132mIncorrect**Answer: 1) Quantity I > Quantity II**

**Explanation:**

Let the length and breadth of rectangle be 5x and 4x respectively.

5x*3x = 1500

X = 10, length = 5*10 = 50 and breadth = 3*10 = 30

Perimeter of rectangle = 2(50+30) = 160 m

Area of circle = 1500-114 = 1386sq m

22/7 r^{2}= 1386

r= 21

Circumference of circle = 2 * 22/7* 21 = 132m - Question 5 of 10
##### 5. Question

1 pointsCategory: Quantitative Aptitude**What is the volume of the solid metal cone?**

**Statement: 1 The slant height of the cone is “x” cm.**

**Statement: 2 The difference between total surface area and curved surface of the cone is “y” cm.**Correct**Answer: 5) The data given in both statements I and II together are necessary to answer the question.**

**Explanation:**

Statement:1 Slant height is given.

Statement:2 Total Surface area of cone =**(πrL + πr**^{2})

Curved surface area of cone =**πrL**

Difference = (πrL + πr^{2}) – πrL =**πr**(Hence,^{2}**radius**can be obtained)

**Combining statements**

In statement 1**slant height**is given,

form statement 2**radius**can be obtained

Using radius and slant height (**height**of cone can be obtained)

Hence,**volume = (1/3)* (πr**can be obtained^{2})*hIncorrect**Answer: 5) The data given in both statements I and II together are necessary to answer the question.**

**Explanation:**

Statement:1 Slant height is given.

Statement:2 Total Surface area of cone =**(πrL + πr**^{2})

Curved surface area of cone =**πrL**

Difference = (πrL + πr^{2}) – πrL =**πr**(Hence,^{2}**radius**can be obtained)

**Combining statements**

In statement 1**slant height**is given,

form statement 2**radius**can be obtained

Using radius and slant height (**height**of cone can be obtained)

Hence,**volume = (1/3)* (πr**can be obtained^{2})*h - Question 6 of 10
##### 6. Question

1 pointsCategory: Quantitative Aptitude**Directions (6-10): There are four companies (P, Q, R, and S) in which 2000 employees (male + female) work together. The ratio of the number of males and females in all four companies together is 3:2. The total number of males in company P is 250 and the total workers in company P are 450. The ratio of the number of female workers in company P, R, and S is 5:6:4. An equal number of male and female work in company Q. The ratio of the total workers in company R and S is 3:2.****Find the total number of workers in company R and S?**Correct**Answer: 1. 1150**

Explanation

Total = 690+460 = 1150

Complete Explanation:

Total workers in all four companies = 2000

Number of males in all four companies = 2000*(3/5) = 1200

Number of females in all four companies = 2000-1200 = 800

Total males in company P = 250

Total females in company P = Total workers – total male workers = 450 – 250 =200

The ratio of the number of female workers in company P, R, and S is 5:6:4

Let the number of female workers in company P, R and S are 5x, 6x and 4x respectively

5x = 200

x = 40

6x = 6*40 = 240

4x =4*40 = 160

Total females in Q = 800-(200+240+160) = 200

In company Q, male = female = 200

Let the number of males in company R and S are y and z respectively.

y + z = 1200 – (250+200) = 750 ………….(1)

also,

(y+240)/(z+160) = 3/2

2y = 3z (putting this in equation (1)

y+z = 750

2y+2z = 1500

3z+2z = 1500

z = 300

therefore, y = 450

Incorrect**Answer: 1. 1150**

Explanation

Total = 690+460 = 1150

Complete Explanation:

Total workers in all four companies = 2000

Number of males in all four companies = 2000*(3/5) = 1200

Number of females in all four companies = 2000-1200 = 800

Total males in company P = 250

Total females in company P = Total workers – total male workers = 450 – 250 =200

The ratio of the number of female workers in company P, R, and S is 5:6:4

Let the number of female workers in company P, R and S are 5x, 6x and 4x respectively

5x = 200

x = 40

6x = 6*40 = 240

4x =4*40 = 160

Total females in Q = 800-(200+240+160) = 200

In company Q, male = female = 200

Let the number of males in company R and S are y and z respectively.

y + z = 1200 – (250+200) = 750 ………….(1)

also,

(y+240)/(z+160) = 3/2

2y = 3z (putting this in equation (1)

y+z = 750

2y+2z = 1500

3z+2z = 1500

z = 300

therefore, y = 450

- Question 7 of 10
##### 7. Question

1 pointsCategory: Quantitative Aptitude**Directions (6-10): There are four companies (P, Q, R, and S) in which 2000 employees (male + female) work together. The ratio of the number of males and females in all four companies together is 3:2. The total number of males in company P is 250 and the total workers in company P are 450. The ratio of the number of female workers in company P, R, and S is 5:6:4. An equal number of male and female work in company Q. The ratio of the total workers in company R and S is 3:2.****Find the difference between the total number of females in company P and R to the total number of males in company Q and S.**Correct**Answer: 3) 60**

Explanation

Males (Q+S) = 200+300 = 500

Females (P+R) = 200+240 = 440

Difference = 500-440 = 60Incorrect**Answer: 3) 60**

Explanation

Males (Q+S) = 200+300 = 500

Females (P+R) = 200+240 = 440

Difference = 500-440 = 60 - Question 8 of 10
##### 8. Question

1 pointsCategory: Quantitative Aptitude**Directions (6-10): There are four companies (P, Q, R, and S) in which 2000 employees (male + female) work together. The ratio of the number of males and females in all four companies together is 3:2. The total number of males in company P is 250 and the total workers in company P are 450. The ratio of the number of female workers in company P, R, and S is 5:6:4. An equal number of male and female work in company Q. The ratio of the total workers in company R and S is 3:2.****The number of females in company R is what percent less than the number of males in company S?**Correct**Answer: 3) 20%**

Explanation

Females(R) = 240

Males (S) = 300

Difference = 300-240 = 60

Required percentage = (60/300)*100 = 20%Incorrect**Answer: 3) 20%**

Explanation

Females(R) = 240

Males (S) = 300

Difference = 300-240 = 60

Required percentage = (60/300)*100 = 20% - Question 9 of 10
##### 9. Question

1 pointsCategory: Quantitative Aptitude**Find the ratio of the total number of females in company P and company S to the total number of males in company P and company Q.**Correct**Answer: 3) 4:5**

Explanation

Females(P+S) = 200+160 = 360

Males (P+Q) = 250+200 = 450

Required ratio = 360:450 = 4:5Incorrect**Answer: 3) 4:5**

Explanation

Females(P+S) = 200+160 = 360

Males (P+Q) = 250+200 = 450

Required ratio = 360:450 = 4:5 - Question 10 of 10
##### 10. Question

1 pointsCategory: Quantitative Aptitude**The total number of males in company P, R and S is what percent of the total number of females in all the companies?**Correct**Answer: 4) 125%**

Explanation

Males (P+R+S) = total males – males(Q)

= 1200 – 200

=1000

Total females = 800

Required percentage = (1000/800)*100 = 125%Incorrect**Answer: 4) 125%**

Explanation

Males (P+R+S) = total males – males(Q)

= 1200 – 200

=1000

Total females = 800

Required percentage = (1000/800)*100 = 125%

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