# SBI PO 2017: Reasoning Test – Day 11

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- Question 1 of 10
##### 1. Question

1 pointsCategory: Reasoning**Q(1-5)**:**Seating Arrangement**Ten persons, A through J, are sitting around a circular table, in ten equally spaced chairs. The table below presents the number of persons sitting between two persons, not necessarily in one specific direction (clockwise or anticlockwise):

**Who is sitting opposite E?**Correct**Explanation:**

Let the figure represent the table with seats numbered from 1 to 10.

Given that between C and G. there are four people, Let C be at I and G be at 6.

Between G and H, there are 7 people. Hence. H can be at 4 or 8.

Let H be at 4. Between H and E there are 8 people (i.e., they are sitting next to each other). Therefore, E can be at 5 or 3. If E is at 3, between E and C there will not be 5(or 3 people). Hence E must be at 5.

Between E and A, there must be three people. A can be at 1 or 9. Since C is at 1. A must be at 9. Between A and I, there are three people. I can be at 3 or 5. Since E is at 5. I must be at 3. I and D are opposite each other. Hence, D must be at 8. Between J and I, there are five people. Hence J must be at 7. Between F and D, there are three people. Hence. F must be at 2 and B must be at 10.

If H is at 8, it will result in the same arrangement but in the anticlockwise direction.

Therefore, two cases are possible which are tabulated below:

Incorrect**Explanation:**

Let the figure represent the table with seats numbered from 1 to 10.

Given that between C and G. there are four people, Let C be at I and G be at 6.

Between G and H, there are 7 people. Hence. H can be at 4 or 8.

Let H be at 4. Between H and E there are 8 people (i.e., they are sitting next to each other). Therefore, E can be at 5 or 3. If E is at 3, between E and C there will not be 5(or 3 people). Hence E must be at 5.

Between E and A, there must be three people. A can be at 1 or 9. Since C is at 1. A must be at 9. Between A and I, there are three people. I can be at 3 or 5. Since E is at 5. I must be at 3. I and D are opposite each other. Hence, D must be at 8. Between J and I, there are five people. Hence J must be at 7. Between F and D, there are three people. Hence. F must be at 2 and B must be at 10.

If H is at 8, it will result in the same arrangement but in the anticlockwise direction.

Therefore, two cases are possible which are tabulated below:

- Question 2 of 10
##### 2. Question

1 pointsCategory: Reasoning**Q(1-5)**:**Seating Arrangement**Ten persons, A through J, are sitting around a circular table, in ten equally spaced chairs. The table below presents the number of persons sitting between two persons, not necessarily in one specific direction (clockwise or anticlockwise):

**If there is exactly one person sitting between E and J, who is sitting to the left of B?**CorrectIncorrect - Question 3 of 10
##### 3. Question

1 pointsCategory: Reasoning**Q(1-5)**:**Seating Arrangement**Ten persons, A through J, are sitting around a circular table, in ten equally spaced chairs. The table below presents the number of persons sitting between two persons, not necessarily in one specific direction (clockwise or anticlockwise):

**Who among the following is sitting next to A?**Correct**Explanation:**

B and D are sitting next to A but only D is given in Question hence has to mark DIncorrect**Explanation:**

B and D are sitting next to A but only D is given in Question hence has to mark D - Question 4 of 10
##### 4. Question

1 pointsCategory: Reasoning**Q(1-5)**:**Seating Arrangement****If the person to the left of A and the person to the right of G are sitting next to each other, who is sitting to the left of C?**CorrectIncorrect - Question 5 of 10
##### 5. Question

1 pointsCategory: Reasoning**Q(1-5)**:**Seating Arrangement****Who is sitting opposite to C?**CorrectIncorrect - Question 6 of 10
##### 6. Question

1 pointsCategory: Reasoning**Direction: Q(6-8)**In code language, ‘0’ is represented as ‘$’ and ‘1’ is represented as ‘α’. For numbers greater than 1 only two symbols given above are to be used. The value of symbol for ‘1’ doubles itself every time it shifts one place to the left.

**For example:**

0 is written as $, 1 is written as α, 2 is written as α$, 3 is written as αα.**Which of the following represents 59?**Correct**Explanation:**

59 can be written in binary form as follows:

=(1+2^{5})+(1* 2^{4)}+(1* 2^{3})+(0*2^{2}) +(1* 2^{1})+ (1×2^{0})

=ααα$ααIncorrect**Explanation:**

59 can be written in binary form as follows:

=(1+2^{5})+(1* 2^{4)}+(1* 2^{3})+(0*2^{2}) +(1* 2^{1})+ (1×2^{0})

=ααα$αα - Question 7 of 10
##### 7. Question

1 pointsCategory: Reasoning**Direction: Q(6-8)**In code language, ‘0’ is represented as ‘$’ and ‘1’ is represented as ‘α’. For numbers greater than 1 only two symbols given above are to be used. The value of symbol for ‘1’ doubles itself every time it shifts one place to the left.

**For example:**

0 is written as $, 1 is written as α, 2 is written as α$, 3 is written as αα.**Which of the following will represent the value of (αα$α * αα$)?**Correct**Explanation:**

αα$α=2^{3}+ 2^{2}+ (0 x 2^{1}) + 2^{0}=13

αα$= 2^{2}+2^{1}+(0x2^{0}) = 6

(α$α X α$) = (13 x 6) = 78

78 can be written in binary form as follows:

=2^{6}+(2^{3})+2^{2}+(2^{1})

α$$ααα$Incorrect**Explanation:**

αα$α=2^{3}+ 2^{2}+ (0 x 2^{1}) + 2^{0}=13

αα$= 2^{2}+2^{1}+(0x2^{0}) = 6

(α$α X α$) = (13 x 6) = 78

78 can be written in binary form as follows:

=2^{6}+(2^{3})+2^{2}+(2^{1})

α$$ααα$ - Question 8 of 10
##### 8. Question

1 pointsCategory: Reasoning**Direction: Q(6-8)**In code language, ‘0’ is represented as ‘$’ and ‘1’ is represented as ‘α’. For numbers greater than 1 only two symbols given above are to be used. The value of symbol for ‘1’ doubles itself every time it shifts one place to the left.

**For example:**

0 is written as $, 1 is written as α, 2 is written as α$, 3 is written as αα.**Which of the following number will be represented by α$α$αα$?**Correct**Explanation:**

α$α$αα$

=2^{6}+ 2^{4}+ 2^{2}+2^{1}= 64+16+4+2=86Incorrect**Explanation:**

α$α$αα$

=2^{6}+ 2^{4}+ 2^{2}+2^{1}= 64+16+4+2=86 - Question 9 of 10
##### 9. Question

1 pointsCategory: Reasoning**Convert to (79)**_{10}hexa system?Correct**Explanation:**

79=1001111

[100][1111]=[4][15]=4FIncorrect**Explanation:**

79=1001111

[100][1111]=[4][15]=4F - Question 10 of 10
##### 10. Question

1 pointsCategory: Reasoning**Convert****(1728)**_{10}to hexadecimal number.Correct**Explanation:**

Incorrect**Explanation:**

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