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- Question 1 of 10
##### 1. Question

1 pointsCategory: Quantitative Aptitude**Directions (1-5) The sum of length of two trains and the time taken to cross each other when travelling in opposite direction of each other is given in first and second line chart respectively.**

Length of the train is in meter and time taken to cross each other when travelling in opposite direction of each other is in seconds.

**Find the time taken by train P and R to cross each other if both are travelling in opposite direction.**Correct**Answer – 4)12.8 seconds**

Explanation –

(35+29) / (1.9+3.1) = 64 / 5 = 12.8 seconds

**Complete Explanation –**

Let, the length of trains (in meter) P, Q, R, S and T is p, q, r, s, t respectively.

And, speed of trains (in m/s) P, Q, R, S and T is a, b, c, d and e respectively.

2*( p+q+r+s+t ) = (72+66+60+64+68)

2*(72+60+t) = 330

T = 33

T+P = 68

33 + P = 68

P = 35

Similarly,

Q = 37

R = 29

S = 31

When, Train P and Q cross each other,

(p + q) / (a+b) = 15

72 / (a+b) = 15

(a+b) = 72/15

(a+b) = 4.8 m/s

Similarly, (b+c) = 6 m/s

c + d = 5 m/s

d + e = 4 m/s

e + a = 4 m/s

2*(a+b+c+d+e) = 23.8

2*(4.8+5+e) = 23.8

e = 2.1 m/s

a = 1.9 m/s

d = 1.9 m/s

c = 3.1 m/s

b = 2.9 m/s

Incorrect**Answer – 4)12.8 seconds**

Explanation –

(35+29) / (1.9+3.1) = 64 / 5 = 12.8 seconds

**Complete Explanation –**

Let, the length of trains (in meter) P, Q, R, S and T is p, q, r, s, t respectively.

And, speed of trains (in m/s) P, Q, R, S and T is a, b, c, d and e respectively.

2*( p+q+r+s+t ) = (72+66+60+64+68)

2*(72+60+t) = 330

T = 33

T+P = 68

33 + P = 68

P = 35

Similarly,

Q = 37

R = 29

S = 31

When, Train P and Q cross each other,

(p + q) / (a+b) = 15

72 / (a+b) = 15

(a+b) = 72/15

(a+b) = 4.8 m/s

Similarly, (b+c) = 6 m/s

c + d = 5 m/s

d + e = 4 m/s

e + a = 4 m/s

2*(a+b+c+d+e) = 23.8

2*(4.8+5+e) = 23.8

e = 2.1 m/s

a = 1.9 m/s

d = 1.9 m/s

c = 3.1 m/s

b = 2.9 m/s

- Question 2 of 10
##### 2. Question

1 pointsCategory: Quantitative Aptitude**Directions (1-5) The sum of length of two trains and the time taken to cross each other when travelling in opposite direction of each other is given in first and second line chart respectively.**

Length of the train is in meter and time taken to cross each other when travelling in opposite direction of each other is in seconds.

**Time taken by train Q to pass train T if they are travelling in the same direction.**Correct**Answer- 2) 87.5 seconds**

Explanation –

(33+37) / (2.9-2.1) = 70 / .8 = 87.5 secondsIncorrect**Answer- 2) 87.5 seconds**

Explanation –

(33+37) / (2.9-2.1) = 70 / .8 = 87.5 seconds - Question 3 of 10
##### 3. Question

1 pointsCategory: Quantitative Aptitude**Directions (1-5) The sum of length of two trains and the time taken to cross each other when travelling in opposite direction of each other is given in first and second line chart respectively.**

Length of the train is in meter and time taken to cross each other when travelling in opposite direction of each other is in seconds.

**If train R crossed a platform of certain length in 21 seconds then find the approximate time taken by train T to cross the same platform.**Correct**Answer -1) 33**

Explanation-

Let, the length of platform = x meter

(29+x) / 3.1 = 21

X = 36.1

Time taken by T to cross same platform

(36.1 + 33 ) / 2.1 = 33 secondsIncorrect**Answer -1) 33**

Explanation-

Let, the length of platform = x meter

(29+x) / 3.1 = 21

X = 36.1

Time taken by T to cross same platform

(36.1 + 33 ) / 2.1 = 33 seconds - Question 4 of 10
##### 4. Question

1 pointsCategory: Quantitative Aptitude

Length of the train is in meter and time taken to cross each other when travelling in opposite direction of each other is in seconds.

**Train S was travelling from Kanpur to Lucknow while train P was travelling from Lucknow to Kanpur. Train S started after 3 hours of train P. If both the trains meet at a distance of 150 km from Lucknow then find the (approximate) distance between Kanpur and Lucknow.**Correct**Answer: 4) 280km**

Explanation–

Speed of train P = 18 /5 * 1.9 = 6.84 km/h

Speed of train S = 18 /5 *1.9 = 6.84 km/h

Time taken by P to travel 150 km = 150 / 6.84 = 22 hr (approx)

Total time taken by S = 22 – 3 = 19 hr

Distance travelled by S = 6.84 * 19 = 130 km (approx)

Required distance = 130 + 150 = 280 (approx)Incorrect**Answer: 4) 280km**

Explanation–

Speed of train P = 18 /5 * 1.9 = 6.84 km/h

Speed of train S = 18 /5 *1.9 = 6.84 km/h

Time taken by P to travel 150 km = 150 / 6.84 = 22 hr (approx)

Total time taken by S = 22 – 3 = 19 hr

Distance travelled by S = 6.84 * 19 = 130 km (approx)

Required distance = 130 + 150 = 280 (approx) - Question 5 of 10
##### 5. Question

1 pointsCategory: Quantitative Aptitude

Length of the train is in meter and time taken to cross each other when travelling in opposite direction of each other is in seconds.

**Train R and train S were travelling from station A to station B which is 108 km apart. If both reached the station B at the same time then find after how much time (approx in hours) of train S, would train R leaved station A?**Correct**Answer- 3) 6 hr**

Explanation–

Speed of train R = 3.1 * 18/5 = 11.16 km/h

Speed of train S = 1.9 * 18/5 = 6.84 km/h

Time taken by R = 108 / 11.16 = 9.68 hours (approx)

Time taken by S = 108 / 6.84 = 15.79 hours (approx)

Difference = 15.79 – 9.68 = 6.11 hoursIncorrect**Answer- 3) 6 hr**

Explanation–

Speed of train R = 3.1 * 18/5 = 11.16 km/h

Speed of train S = 1.9 * 18/5 = 6.84 km/h

Time taken by R = 108 / 11.16 = 9.68 hours (approx)

Time taken by S = 108 / 6.84 = 15.79 hours (approx)

Difference = 15.79 – 9.68 = 6.11 hours - Question 6 of 10
##### 6. Question

1 pointsCategory: Quantitative AptitudeDirections (6-10)There are 3 types of departments namely Electrical, Electronics and Telecommunication in a company and certain number of people were working in all three departments. Each person was working on one department or the other. 64% people where in Electrical department. People working in Telecommunication department only were 1/16 of the Electrical department. Person working in both Electronics and Telecommunication department except Electrical department were 55. Person working in only Electronics department is equal to person in Telecommunication department only + 29.

**What is the total number of people working in Electronics department only?**Correct**Answer-1) 41**

Explanation:

People working in Electronics department only = 4x + 29 =12+29 =41

**Complete Explanation –**

Let Electrical is denoted as El, electronics only as Et and Telecommunications only is denoted as T

Let the no. of people working in the company = 100x

People working in Electrical department = 64% of 100x = 64x

People working in Telecommunication department only = 1/16 * 64x = 4x

People working in both Electronics and Telecommunication department except Electrical department = 55

People working in Electronics department only = 4x +29

Total = 100x

100x = 64x +4x+29 +55 + 4x

28x = 84

x = 3

Therefore total people = 100x = 100*3 = 300

People working in Electrical department = 64x = 64*3 = 192

People working in Telecommunication department only = 1/16 * 64x = 4x = 4*3 = 12

People working in both Electronics and Telecommunication department except Electrical department = 55

People working in Electronics department only = 4x + 29 =12+29 =41Incorrect**Answer-1) 41**

Explanation:

People working in Electronics department only = 4x + 29 =12+29 =41

**Complete Explanation –**

Let Electrical is denoted as El, electronics only as Et and Telecommunications only is denoted as T

Let the no. of people working in the company = 100x

People working in Electrical department = 64% of 100x = 64x

People working in Telecommunication department only = 1/16 * 64x = 4x

People working in both Electronics and Telecommunication department except Electrical department = 55

People working in Electronics department only = 4x +29

Total = 100x

100x = 64x +4x+29 +55 + 4x

28x = 84

x = 3

Therefore total people = 100x = 100*3 = 300

People working in Electrical department = 64x = 64*3 = 192

People working in Telecommunication department only = 1/16 * 64x = 4x = 4*3 = 12

People working in both Electronics and Telecommunication department except Electrical department = 55

People working in Electronics department only = 4x + 29 =12+29 =41 - Question 7 of 10
##### 7. Question

1 pointsCategory: Quantitative AptitudeDirections (6-10)There are 3 types of departments namely Electrical, Electronics and Telecommunication in a company and certain number of people were working in all three departments. Each person was working on one department or the other. 64% people where in Electrical department. People working in Telecommunication department only were 1/16 of the Electrical department. Person working in both Electronics and Telecommunication department except Electrical department were 55. Person working in only Electronics department is equal to person in Telecommunication department only + 29.

**What is the total number of people working in the company?**Correct**Answer- 2) 300**

Explanation

Let the no. of people working in the company = 100x

100x = 64x +4x+29 +55 + 4x

28x = 84

x = 3Incorrect**Answer- 2) 300**

Explanation

Let the no. of people working in the company = 100x

100x = 64x +4x+29 +55 + 4x

28x = 84

x = 3 - Question 8 of 10
##### 8. Question

1 pointsCategory: Quantitative AptitudeDirections (6-10)There are 3 types of departments namely Electrical, Electronics and Telecommunication in a company and certain number of people were working in all three departments. Each person was working on one department or the other. 64% people where in Electrical department. People working in Telecommunication department only were 1/16 of the Electrical department. Person working in both Electronics and Telecommunication department except Electrical department were 55. Person working in only Electronics department is equal to person in Telecommunication department only + 29.

**What is the difference between the number of people working in both Electronics and Telecommunication department except Electrical department to the sum of the number of people working in Telecommunication department only and Electronics department only?**Correct**Answer- 4) 2**

Explanation

55 – (41+12) = 2Incorrect**Answer- 4) 2**

Explanation

55 – (41+12) = 2 - Question 9 of 10
##### 9. Question

1 pointsCategory: Quantitative Aptitude**What is the total number of people working in Electrical department?**Correct**Answer- 5) 192**

Explanation-

People working in Electrical department = 64% of 100x = 64x = 64*3 = 192Incorrect**Answer- 5) 192**

Explanation-

People working in Electrical department = 64% of 100x = 64x = 64*3 = 192 - Question 10 of 10
##### 10. Question

1 pointsCategory: Quantitative Aptitude**If 50 people are working in both electrical and telecommunication except electronics department and 22 people are working in both electrical and electronics department except telecommunication department, then find the number of people working in electrical department only if no one is working in all three departments?**Correct**Answer- 2) 120**

Explanation–

192 – (50+22) = 120Incorrect**Answer- 2) 120**

Explanation–

192 – (50+22) = 120

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