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- Question 1 of 10
##### 1. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q1-5). The line graph below gives information about the number of days taken by 5 men A, B, C, D and E to complete a particular work. The bar graph gives information about the number of days taken by 4 women P, Q, R and S to complete the same work and table below gives information about the number of days taken by 3 children X, Y and Z to complete the same piece of work.**

**A and R started the work together but A left the work after 5 days. The rest of the work was completed by R alone with 25% of his original efficiency. Total number of days taken by them to complete the whole work is:**Correct**Answer- 3) 73**

Explanation-

We have,

Work completed by A and R together = (2 + 1) × 5 = 3 × 5 = 15

Remaining work = 32 – 15 = 17

Time taken by R to complete the remaining work = 17/(1/4) = 68 days

Total number of days = 68 + 5 = 73 daysIncorrect**Answer- 3) 73**

Explanation-

We have,

Work completed by A and R together = (2 + 1) × 5 = 3 × 5 = 15

Remaining work = 32 – 15 = 17

Time taken by R to complete the remaining work = 17/(1/4) = 68 days

Total number of days = 68 + 5 = 73 days - Question 2 of 10
##### 2. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q1-5). The line graph below gives information about the number of days taken by 5 men A, B, C, D and E to complete a particular work. The bar graph gives information about the number of days taken by 4 women P, Q, R and S to complete the same work and table below gives information about the number of days taken by 3 children X, Y and Z to complete the same piece of work.**

**Approximately how many days will be taken by A, B, R and S to complete double of original work?**Correct**Answer- 3) 13 days**

Explanation-

No of days taken by them to complete double of original work = 2 × 2400 / (150 + 96 + 75 + 50) = 4800/371 = 13 days (approx.)Incorrect**Answer- 3) 13 days**

Explanation-

No of days taken by them to complete double of original work = 2 × 2400 / (150 + 96 + 75 + 50) = 4800/371 = 13 days (approx.) - Question 3 of 10
##### 3. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q1-5). The line graph below gives information about the number of days taken by 5 men A, B, C, D and E to complete a particular work. The bar graph gives information about the number of days taken by 4 women P, Q, R and S to complete the same work and table below gives information about the number of days taken by 3 children X, Y and Z to complete the same piece of work.**

**15 men having efficiencies same as that of E can do a piece of work in 27 days. How many children of efficiencies same as that of X can do 4 times of this work in 18 days?**Correct**Answer- 4) 270**

Explanation-

Let the required number of children be x.

Since E can do a piece of work in 18 days and X can do the same piece of work in 54 days, the efficiency of E is three times to that of X.

We have,

18 × x /4 = 15 × 27 × 3

By solving we have, x = 270Incorrect**Answer- 4) 270**

Explanation-

Let the required number of children be x.

Since E can do a piece of work in 18 days and X can do the same piece of work in 54 days, the efficiency of E is three times to that of X.

We have,

18 × x /4 = 15 × 27 × 3

By solving we have, x = 270 - Question 4 of 10
##### 4. Question

1 pointsCategory: Quantitative Aptitude

**Which of the following combinations of a man, a woman and a boy will take least time to complete the work?**Correct**Answer- 4) A, R, Z**

Explanation-

To calculate the number of days taken by B, R and Z to complete the work together, we have,

Incorrect**Answer- 4) A, R, Z**

Explanation-

To calculate the number of days taken by B, R and Z to complete the work together, we have,

- Question 5 of 10
##### 5. Question

1 pointsCategory: Quantitative Aptitude

**Approximately how many days will be taken by P, Q and S to complete three times of original work?**Correct**Answer- 5) 41 days**

Explanation- We have,

Incorrect**Answer- 5) 41 days**

Explanation- We have,

- Question 6 of 10
##### 6. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q6-10). The line graph below shows the percentage discount offered on six articles A, B, C, D, E and F by three stores X, Y and Z.**

The marked prize of the articles is shown by the table which is same in every store. Few values are missing in the table.

**What is the difference between selling prize of article B in store Y and that of in store Z?**Correct**Answer- 1) Rs 82**

Explanation-

Difference = (16 – 8) % of 1025 = Rs 82Incorrect**Answer- 1) Rs 82**

Explanation-

Difference = (16 – 8) % of 1025 = Rs 82 - Question 7 of 10
##### 7. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q6-10). The line graph below shows the percentage discount offered on six articles A, B, C, D, E and F by three stores X, Y and Z.**

The marked prize of the articles is shown by the table which is same in every store. Few values are missing in the table.

**The Marked Prize of the article E is 760/41% more than that of article B. What is the average selling price of the article E in all three stores together?**Correct**Answer- 5) Rs 882.9**Marked price of the article E = 1025 + 760/41% of 1025 = 1025 + 190 = Rs 1215

Explanation-

Selling price of the article in store X = (100 – 25) % of 1215 = 75% of 1215 = Rs 911.25

Selling price of the article in store Y = (100 – 33) % of 1215 = 67% of 1215 = Rs 814.05

Selling price of the article in store Z = (100 – 24) % of 1215 = 76% of 1215 = Rs 923.4

Required average = (911.25 + 814.05 + 923.4)/3 = 2648.7/3 = Rs 882.9Incorrect**Answer- 5) Rs 882.9**Marked price of the article E = 1025 + 760/41% of 1025 = 1025 + 190 = Rs 1215

Explanation-

Selling price of the article in store X = (100 – 25) % of 1215 = 75% of 1215 = Rs 911.25

Selling price of the article in store Y = (100 – 33) % of 1215 = 67% of 1215 = Rs 814.05

Selling price of the article in store Z = (100 – 24) % of 1215 = 76% of 1215 = Rs 923.4

Required average = (911.25 + 814.05 + 923.4)/3 = 2648.7/3 = Rs 882.9 - Question 8 of 10
##### 8. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q6-10). The line graph below shows the percentage discount offered on six articles A, B, C, D, E and F by three stores X, Y and Z.**

The marked prize of the articles is shown by the table which is same in every store. Few values are missing in the table.

**The difference between the selling price of the article A in store X and that of in store Y is Rs 28.5. What is the selling price of the article in store Z?**Correct**Answer- 1) Rs 864.5**Let the marked price of the article is Rs x.

Explanation-

Then, (15 – 12) % of x = 28.5

Therefore, x = 28.5/3 × 100 = Rs 950

Selling price in store Z = 91% of 950 = Rs 864.5Incorrect**Answer- 1) Rs 864.5**Let the marked price of the article is Rs x.

Explanation-

Then, (15 – 12) % of x = 28.5

Therefore, x = 28.5/3 × 100 = Rs 950

Selling price in store Z = 91% of 950 = Rs 864.5 - Question 9 of 10
##### 9. Question

1 pointsCategory: Quantitative Aptitude

The marked prize of the articles is shown by the table which is same in every store. Few values are missing in the table.

**The cost price of the article F is Rs 654 for every store. Approximately what is the average profit earned by each store by selling article F?**Correct**Answer- 3) Rs 45**

Explanation-

Selling price of the article F for store X = 78% of 936 = Rs 730.08

Profit earned by store X = 730.08 – 654 = Rs 76.08

Selling price of the article for store Y = 74% of 936 = Rs 692.64

Profit earned by store Y = 692.64 – 654 = Rs 38.64

Selling price of the article for store Z = 72% of 936 = Rs 673.92

Profit earned by store Z = 673.92 – 654 = Rs 19.92

Required average = (76.08 + 38.64 + 19.92)/3 = 134.64/3 = Rs 45 (approx.)Incorrect**Answer- 3) Rs 45**

Explanation-

Selling price of the article F for store X = 78% of 936 = Rs 730.08

Profit earned by store X = 730.08 – 654 = Rs 76.08

Selling price of the article for store Y = 74% of 936 = Rs 692.64

Profit earned by store Y = 692.64 – 654 = Rs 38.64

Selling price of the article for store Z = 72% of 936 = Rs 673.92

Profit earned by store Z = 673.92 – 654 = Rs 19.92

Required average = (76.08 + 38.64 + 19.92)/3 = 134.64/3 = Rs 45 (approx.) - Question 10 of 10
##### 10. Question

1 pointsCategory: Quantitative Aptitude

The marked prize of the articles is shown by the table which is same in every store. Few values are missing in the table.

**The average selling price of the article C for all the three stores is Rs 10048/15. What is the marked price of the article C?**Correct**Answer- 5) Rs 785**

Explanation-

Let the marked price of the article C is Rs x

Then, selling price of the article for store X = 79% of x = Rs 0.79x

Selling price of the article for store Y = 91% of x = Rs 0.91x

Selling price of the article for store Z = 86% of x = Rs 0.86x

Average selling price = (0.79x + 0.91x + 0.86x)/3 = 2.56x/3

According to the question, we have,

2.56x/3 = 10048/15

Therefore, x = 10048 × 3/(15 × 2.56) = Rs 785Incorrect**Answer- 5) Rs 785**

Explanation-

Let the marked price of the article C is Rs x

Then, selling price of the article for store X = 79% of x = Rs 0.79x

Selling price of the article for store Y = 91% of x = Rs 0.91x

Selling price of the article for store Z = 86% of x = Rs 0.86x

Average selling price = (0.79x + 0.91x + 0.86x)/3 = 2.56x/3

According to the question, we have,

2.56x/3 = 10048/15

Therefore, x = 10048 × 3/(15 × 2.56) = Rs 785

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